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11111nata11111 [884]
3 years ago
14

What type of number is 3π+1?

Mathematics
2 answers:
777dan777 [17]3 years ago
7 0

Answer:

10.42478

Step-by-step explanation:

Sergeu [11.5K]3 years ago
4 0

Answer:

irrational

Step-by-step explanation:

I hope it helped you!!

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Solve : X^2 - 3x = -8<br><br><br> And <br><br><br> Solve : -2x^2 - 16x - 44 = 0
Aleonysh [2.5K]

Answer:

X = 8/3 + X^2/3

X = -4 ± i\sqrt{6}

Step-by-step explanation:

5 0
4 years ago
Simplify the following expression.
expeople1 [14]

Answer: 3x^{2}-24x


Step-by-step explanation:

 1. To simplify the expression given in the problem, you must apply a property of exponents called Quotient of powers, which states that when you divide two powers that have the same base, you must subtract the exponents.

2. Keeping this property on mind you have, you can rewrite the expression as following and simplify:

 \frac{-12x^{4}}{-4x}+\frac{96x^{2}}{-4x}=3x^{2}-24x



3 0
3 years ago
When two equal forces are inclined at an angle 2a their resultant is twice as great as
swat32

Step-by-step answer:

Referring to the attached diagram, the resultant of two forces each with magnitude F and inclined to each other at 2a equals

Ra = 2Fcos(a) ..............................(1)

Similarly, the resultant of two forces each with magnitude F and inclined to each other at 2b equals

Rb = 2Fcos(b)..............................(2)

We are given that

Ra = 2Rb  ....................................(3)

Substitute (1) & (2) in (3) gives

2Fcos(a) = 2(2Fcos(b))

Expand

2Fcos(a) = 4Fcos(b)

Simplify

cos(a) = 2 cos(b)   QED

Note: Please note that you might have a faster response if you posted this question in the physics or the (new) Engineering section.

Have a nice day!

5 0
3 years ago
. All the students in SS3 of a named school take either Mathematics (M), or Physics (P) or Chemistry (C). 40 take Mathematics, 4
aivan3 [116]

Answer:

(a) = 13

(b) = 8

(c) = 5

Step-by-step explanation:

Addition theorems on sets are

Theorem 1 :

n(AuB) = n(A) + n(B) - n(AnB)

Theorem 2 :

n(AuBuC) : = n(A) + n(B) + n(C) - n(AnB) - n(BnC) - n(AnC) + n(AnBnC)

Total number of students in the school is not given

so let there are 60 students in the school

using theorem 2

n(AuBuC) : = n(A) + n(B) + n(C) - n(AnB) - n(BnC) - n(AnC) + n(AnBnC)

let n(A) = Mathematics, n(B) =Physics and n(C) = Chemistry

so putting values,

   60             =    40 + 42 + 38 - 20 - 28 - 25 + n(AnBnC)

60 +73 -120 = n(AnBnC)

         13         = n(AnBnC)

therefore, there are total 13 students who take all three subjects

Number of students who had taken only Mathematics  =
n(A) - n(AnB) - n(AnC) + n(AnBnC)

40 - 20 - 25 + 13

53 - 45 = 8 students

Number of students who had taken only Physics  =

n(B) - n(BnA) - n(BnC) + n(AnBnC)

42 - 20 - 28 + 13

53 - 48 = 5 students

learn more about sets and vein diagrams at

brainly.com/question/2332158

#SPJ10

4 0
2 years ago
What is the area of the face marked f
Annette [7]

Answer:

12cm ...........

........

5 0
3 years ago
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