This is 3rd grade math i need help please. what are forms of numbers
2 answers:
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Answer:
Equation is;
q/sin 105 = 15/sin 30
Step-by-step explanation:
We are given;
Angle Q = 105°
Angle S = 30°
s = 15
From sine rule we know that;
a/sin A = b/sin B = c/sin C.
Thus, applying that to this question, we can find side q.
Thus;. q/Sin Q = s/Sin S
Plugging in the relevant values to obtain ;
q/sin 105 = 15/sin 30
The solution for the given equations x + 3y = 5 and x - 3y = -1 are x=2 and y=1.
Step-by-step explanation:
The given is,
......................................(1)
....................................(2)
Step:1
By elimination method,
Subtracting Equations (1) and (2),
( - )
( ) + (
) = (
)
= 6
= 1
Step:2
Substitute the value of y in equation (1),
+ ( 3 × 1 ) = 5
= 5-3
= 2
Step:3
Check for Solution,
Substitute the values of x and y in Eqn (1),
2 + ( 3 × 1 ) = 5
5 = 5
Result:
The solution for the given equations x + 3y = 5 and x - 3y = -1 are x=2 and y=1, by elimination method.