If s is the side of the square base, the area of the square base is s^2.
The volume of the square base is,
V = (s²) (h)
s² = V/h
s² = 3n³ + 13n² + 16n + 4 / <span>3n + 1
You can do this division by factoring, synthetic division, or by plain division.
Factoring out 3n + 1 from the numerator gives you:
</span>s² = (3n + 1)(n² + 4n + 4) / 3n+1
s² = n² + 4n + 4
Therefore, the area of the square base is <span>n² + 4n + 4.</span>
Answer:
2i and -2i
Step-by-step explanation:
I'll change u to x to be easier to understand.
x^2 = -4
sqrt(x^2) = sqrt(-4)
sqrt(-4) = 2i, or -2i
9.
<2 and <6 are right angles by the definition of perpendicular lines.
Since corresponding angles are congruent, m || n.
11.
In a triangle, the measures of the three angles add to 180 degrees.
If one angle is a right angle, then that angle measures 90 degrees. The other two angle measures plus 90 degrees add to 180 degrees, so the other two angle measures add to 90 degrees. In a right triangle there is a right angle and two other angles that are complementary.
Now look at your problem.
One angle is a right angle.
The other two angles are complementary, so their measures add to 90 deg.
8x + 2 + 9x + 3 = 90
17x + 5 = 90
17x = 85
x = 5
G(x) is f(x) rotated about the x-axis and then compressed vertically by a factor of 4/5.
