Question

4x^2 + 4x - 8 = 0 solved in a quadratic formula.

Answer 1

I'll teach you how to solve 4x^2 + 4x - 8 = 0

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4x^2 + 4x - 8 = 0

Solve with the quadratic formula:

For   a=4,b=4,c=-8: 1^x,2=-4+- sqrt 4^2-4*4(-8)/2*4

x=  -4+- sqrt 4^2-4*4(-8)/2*4 : 1

x=  -4+- sqrt 4^2-4*4(-8)/2*4 : -2

The solutions to the quadratic equation is:

x=1, x=-2

Your Answer Is x=1, x=-2

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