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polet [3.4K]
3 years ago
12

Two stars have the same luminosity, but Star A is 10.0 times farther away than Star B. How much fainter does Star A appear compa

red to Star B? times fainter
Geography
1 answer:
MariettaO [177]3 years ago
3 0

Answer:

B(A)100=B(B), the star A is 100 times fainter than star B.

Explanation:

Brightness of the star is defined by the formula,

B=\frac{L}{4\pi d^{2}}

Here, L is the luminosity and d is the distance.

For star A, the distance is 10d. The brightness of star A.

B(A)=\frac{L}{4\pi (10d)^{2}}

For star B, the distance is d. The brightness of star B.

B(B)=\frac{L}{4\pi d^{2}}

Now according to the question luminosity of two stars is equal.

Therefore,

B(A){4\pi (10d)^{2}}=B(B){4\pi (d)^{2}}\\B(A)100=B(B)

So, star B is 100 times brighter than star A.

Therefore the star A is 100 times fainter than star B.

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