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3 years ago

15

A ball is dropped from the top of a building. The distance in feet above the ground, represented by h(t), after t seconds can be

modeled by the equation h(t)=-16t^2+180.
What is it's height after 3 seconds of falling?

1 answer:

ikadub [295]3 years ago

3 0

Answer:

324 feet

Step-by-step explanation:

h(3) = 16(3)^2 + 180

h(3) = 16(9) + 180

h(3) = 144 + 180

h(3) = 324

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