Question

Which equation is y = –3x2 – 12x – 2 rewritten in vertex form?

Answer 1

Y=-6-12x-2
y=-6-12x-2
y=-8-12x
y=-8-12x
and these are real numbers

Answer 2

Answer:

The vertex form of the given equation is $y=-3(x+2)^2+10$.

Step-by-step explanation:

The vertex form of a parabola is

$y=a(x-h)^2+k$.

The given equation is

$y=-3x^2-12x-2$

$y=(-3x^2-12x)-2$

Take the common coefficients.

$y=-3(x^2+4x)-2$

If an expression is defined as $x^2+bx$, then we need to add $(\frac{b}{2})^2$ to make it perfect square.

Here b=4, so we need to add $(\frac{4}{2})^2$ in the parenthesis.

$y=-3(x^2+4x+2^2-2^2)-2$

$y=-3(x^2+4x+2^2)-3(-2^2)-2$

$y=-3(x+2)^2-3(-4)-2$

$y=-3(x+2)^2+12-2$

$y=-3(x+2)^2+10$

Therefore the vertex form of the given equation is $y=-3(x+2)^2+10$.