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4 years ago

What is perimeter and how to find it What is area and how to find it

Mathematics

2 answers:

Alexus [3.1K]4 years ago

5 0

<span>perimeter</span> is adding all the sides u multiply for area

Lisa [10]4 years ago

4 0

Perimeter is L+W+L+W
Area is LxW

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Find the annual percentage yield of a bank account that pays 5.3% interest compounded monthly. Round the percent to the nearest

drek231 [11]

It would be 5.3% of a number given. But since there isn't, you would have to use X.

8 0

4 years ago

Solve for [0,2pi): 3sin^2x-6sinx=0

Ainat [17]

Given the equation :

$3\sin ^2x-6\sin x=0$

Let: y = sin x

So,

$\sin ^2x=y^2$

the given equation will be:

$3y^2-6y=0$

Solve for y, take 3y as a common:

$\begin{gathered} 3y(y-2)=0 \\ 3y=0\rightarrow y=0 \\ y-2=0\rightarrow y=2 \end{gathered}$

so,

$\begin{gathered} y=0\rightarrow\sin x=0\rightarrow x=0or\pi \\ y=2\rightarrow\sin x=2 \end{gathered}$

Note: the range of sine function is [ -1, 1]

So, sin x = 2 ( is rejected)

So, the answer will be: x ={ 0 , pi }

3 0

1 year ago

In ΔXYZ the measure of

Delicious77 [7]

Answer:

tan X = $\frac{39}{80}$

Step-by-step explanation:

tan X = $\frac{opposite}{adjacent}$ = $\frac{YZ}{XZ}$ = $\frac{39}{80}$

4 0

3 years ago

Assume Y=1+X+u, where X, Y, and u=v+X are random variables, v is independent of X; E(v)=0, Var(v)=1, E(X)=1, and

kobusy [5.1K]

Answer:

a) $E(u|X=1)= E(v|X=1) + E(X|X=1) = E(v) +1 = 0 +1 =1+$

b) $E(Y| X=1)= E(1|X=1) + E(X|X=1) + E(u|X=1) = E(1) + 1 + E(v) + 0 = 1+1+0=2$

c) $E(u|X=2)= E(v|X=2) + E(X|X=2) = E(v) +2 = 0 +2 =2$

d) $E(Y| X=2)= E(1|X=2) + E(X|X=2) + E(u|X=2) = E(2) + 2 + E(v) + 2 = 2+2+2=6$

e) $E(u|X) = E(v+X |X) = E(v|X) +E(X|X) = E(v) +E(X) = 0+1=1$

f) $E(Y|X) = E(1+X+u |X) = E(1|X) +E(X|X) + E(u|X) = 1+1+1=3$

g) $E(u) = E(v) +E(X) = 0+1=1$

h) E(Y) = E(1+X+u) = E(1) + E(X) +E(v+X) = 1+1 + E(v) +E(X) = 1+1+0+1 = 3[/tex]

Step-by-step explanation:

For this case we know this:

$Y = 1+X +u$

$u = v+X$

with both Y and u random variables, we also know that:

$[tex] E(v) = 0, Var(v) =1, E(X) = 1, Var(X)=2$

And we want to calculate this:

Part a

$E(u|X=1)= E(v+X|X=1)$

Using properties for the conditional expected value we have this:

$E(u|X=1)= E(v|X=1) + E(X|X=1) = E(v) +1 = 0 +1 =1$

Because we assume that v and X are independent

Part b

$E(Y| X=1) = E(1+X+u|X=1)$

If we distribute the expected value we got:

$E(Y| X=1)= E(1|X=1) + E(X|X=1) + E(u|X=1) = E(1) + 1 + E(v) + 0 = 1+1+0=2$

Part c

$E(u|X=2)= E(v+X|X=2)$

Using properties for the conditional expected value we have this:

$E(u|X=2)= E(v|X=2) + E(X|X=2) = E(v) +2 = 0 +2 =2$

Because we assume that v and X are independent

Part d

$E(Y| X=2) = E(1+X+u|X=2)$

If we distribute the expected value we got:

$E(Y| X=2)= E(1|X=2) + E(X|X=2) + E(u|X=2) = E(2) + 2 + E(v) + 2 = 2+2+2=6$

Part e

$E(u|X) = E(v+X |X) = E(v|X) +E(X|X) = E(v) +E(X) = 0+1=1$

Part f

$E(Y|X) = E(1+X+u |X) = E(1|X) +E(X|X) + E(u|X) = 1+1+1=3$

Part g

$E(u) = E(v) +E(X) = 0+1=1$

Part h

E(Y) = E(1+X+u) = E(1) + E(X) +E(v+X) = 1+1 + E(v) +E(X) = 1+1+0+1 = 3[/tex]

8 0

3 years ago

A figure skating school offers introductory lessons at $50 per session. There is also a registration fee of $75.

erica [24]

Answer:

Step-by-step explanation:

a. Y=50x+75

b. Y=50(7)+75

y=350+75

y=425

Yes, you will have enough if you use the 465 certificate. You will have $40 (465-425) left on the gift certificate.

8 0

3 years ago