X^2 +3x-4=0
(X+4)(x-1)=0 so x = -4 and x=1 are solutions
Answer:
<u>The solutions to this quadratic equation are 10 and 3.</u>
Step-by-step explanation:
1. Let's recall the formula for solving this type of equations, called quadratic equations:
x = ( - b +/- √ b² - 4ac)/ 2a
The equation given is x2 – 13x + 30 = 0,
where a = 1, b = - 13 and c = 30
Now replacing with the real values, we have
x = [ - (-13) +/- √ (-13)² - 4 * 1 * 30] / 2 * 1
x = [ 13 +/- √ 169 - 120] / 2
x = [13 +/- √ 49]/ 2
x = [ 13 +/- 7 ]/ 2
<u>x₁ = 13 + 7/2 = 20/2 = 10</u>
<u>x₂ = 13 - 7/2 = 6/2 = 3</u>
Answer:
the answer is two
Step-by-step explanation:
i don't have one but i did the quiz and got it right
Answer: $9.00
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If a=0, then the denominator is equal to 0. Since you cannot divide by zero, you are not allowed to do this.
Hope This helps!
