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Sloan [31]
4 years ago
14

Use the scenario to answer the question.

Mathematics
1 answer:
Doss [256]4 years ago
4 0
in³ are the units associated with volume, V. Arletha's measurement could represent volume.


_____
Area, B, would have units of in². Height, h, would have units of in.
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The half-life of a radioactive kind of ruthenium is 40 days. If you start with 240 grams of it,
Vlad [161]

Answer: 30g

Step-by-step explanation:

In this question (t½) of isotope is 40 days, which means that after 40 days half of the sample would have decayed and half would be left as it is.

After 40 days ( first half life) 240 /2 = 120 g decays and 120 g remains left.

After another 40 days ( two half lives or 80 days) 120 /2 = 60 g decays and 60 g remains left .

after three half lives or 120 days, 60/2 = 30g decay and 30 g of the isotope will be left.

4 0
4 years ago
Horses are measure in units called hands.One inch equals 1/4 hand.The average Clydesdale is 17 1/5 hands tall.What is th is heig
Mashcka [7]
(17.2 hand)*(1 in)/(0.25 hand) = 68.8 in
8 0
4 years ago
Which formula can be used to describe the sequence below 27,9,3​
Ierofanga [76]

Answer:

a_n=27 \cdot (\frac{1}{3})^{n-1}.

Step-by-step explanation:

This is a geometric sequence that means there is a common ratio.  That means there is a number you can multiply over and over to get the next term.

The first term is 27.

The second term is (1/3)(27)=9.

The third term is (1/3)(9)=3.

So the common ratio is 1/3.

That means you can keep multiplying by 1/3 to find the next term in the sequence.

The explicit form for a geometric sequence is a_n=a_1 \cdot r^{n-1} where a_1 is the first term and r is the common ratio.

We are given a_1=27 and r=\frac{1}{3}.

So the explicit form for the given sequence is a_n=27 \cdot (\frac{1}{3})^{n-1}.

3 0
3 years ago
Consider the following functions. f1(x) = x, f2(x) = x2, f3(x) = 7x − 5x2 g(x) = c1f1(x) + c2f2(x) + c3f3(x) Solve for c1, c2, a
Margaret [11]

Answer:

Therefore the solution is = k{-7,5,1} where k ∈R

Step-by-step explanation:

Given that,

f₁(x) =x

f₂(x)= x²

f₃(x)= 7x - 5x²

Also,

g(x) = c₁f₁(x)+c₂f₂(x)+c₃f₃(x)

Putting the values of f₁(x), f₂(x) and f₃(x).

g(x) = c₁.x+c₂x²+c₃(7x-5x²)

Given condition that g(x)= 0

∴ c₁.x+c₂x²+c₃(7x-5x²)=0

⇒(c₁+7c₃)x +(c₂-5c₃)x² = 0

Comparing the coefficients of x and x²

∴c₁+7c₃=0               and       c₂-5c₃ =0

\Rightarrow c_1 =-7c_3                     \Rightarrow c_2=5c_3

Let c₃= k   [k∈R]  

Then c₁ = -7k   and   c₂=5k

Therefore the solution is = { c₁,c₂,c₃}  

                                           = {-7k, 5k, k}

                                            =k{-7,5,1}

5 0
3 years ago
THANKS! Everyone if you answer this
andrew11 [14]

Answer:

Down Below .

Step-by-step explanation:

A. Nickel and Copper.

B. The average temp is 1034.8575. I got that by adding all the temps then dividing it by 4

4 0
3 years ago
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