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Dmitry [639]
3 years ago
15

PLEASE HELP ASAP.!!! ILL GIVE BRAINLIEST *EXTRA POINTS* PLEASE DONT SKIP :((

Mathematics
2 answers:
devlian [24]3 years ago
7 0

Answer:

6

Step-by-step explanation:

2 choices for pants and 3 shirts, so 2*3=6.

grandymaker [24]3 years ago
3 0

Answer:

total outfits = 6

Step-by-step explanation:

3 shirts x 2 pants

you had better give me brainliest

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PLEASE HELP ASAP !!!
BartSMP [9]
You know that a straight line has an angle of 180 degrees; 

48+x+x=180 <-- since they are all on the same time
48+2x=180 
2x=180-48 
2x=132
x=132/2
x=66

Therefore, the x value is 66 degree. 

Hope I helped :) 
8 0
3 years ago
Describe how the graph of the equation relates to the graph of y = x2.<br> f(x) = -x + 5)2
Kobotan [32]

Answer:

Step-by-step explanation:

It's y = x^2, not y = x2.  The graph of y = x^2 is a parabola with vertex (0, 0) and which opens up.

The graph of y = (x + 5)^2 has the same shape as that of y = x^2, but has been translated 5 units to the left.

6 0
3 years ago
Jennifer spent $42 on a magazine and 7 candy bars. The magazine cost $7, then how much was each candy bar​
Genrish500 [490]
$5. You subtract the $7 from the $42 since that was the magazine then you divide that(35) by 7 since that is the amount of candy bars that were bought. That’ll give you the answer of $5 for each candy bar.
3 0
2 years ago
Solving Exponential and Logarithmic Equations In Exercise, solve for x.<br> 500(1.075)120x = 100.000
Volgvan

Answer:

The solution is:

x = 0.61

Step-by-step explanation:

The first step to solve this equation is placing everything with the exponential to one side of the equality, and everything without the exponential to the other side. So

500(1.075)^{120x} = 100000

(1.075)^{120x} = \frac{100000}{500}

(1.075)^{120x} = 200

To find x, we have to apply log to both sides of the equality.

We also have that:

\log{a^{x}} = x\log{a}

So

\log{(1.075)^{120x}} = \log{200}

120x\log{1.075} = 2.30

120x*0.03 = 2.30

3.77x = 2.30

x = \frac{2.30}{3.77}

x = 0.61

4 0
3 years ago
I would really appreciate some help on this.
8_murik_8 [283]

Answer:

1. terms: 4r, 2, -6, and 3r        like terms: 2 and -6, 4r and 3r

2.terms: 5h^2, -3h^2, - 4h, 3h, 7       like terms: 5h^2 and -3h^2, - 4h and 3h

3. 3m + 6

4. 15b + 2

5. 3x + 9

Step-by-step explanation:

1. 4r + 2 - 6 +3r

  terms: 4r, 2, -6, and 3r                     like terms: 2 and -6, 4r and 3r

2. 5h^2 - 3h^2 - 4h + 3h + 7

   terms: 5h^2, -3h^2, - 4h, 3h, 7       like terms: 5h^2 and -3h^2, - 4h and 3h

3. 6m + 7 - 3m-1

   3m + 6

4. 3(5b +2) - 4

   15b + 6 - 4

   15b + 2

5. 2x + 4 + 5 + x

   3x + 9

5 0
3 years ago
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