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3 years ago

The areas of the squares adjacent to two sides of a right triangle are shown below 40 POINTS!!!

Mathematics

2 answers:

Fynjy0 [20]3 years ago

8 0

Answer:

Given a=33 and c=44,

b = 29.10326 = 11√7

Step-by-step explanation:

The following is one way to perform the calculation. It may not be the best way.

b =√c2 - a2

=√442 - 332

=√847

=29.10326 = 11√7

∠α =arcsin(a/c)

=arcsin(33/44)

=arcsin(0.75)

=0.84806 rad = 48.59° = 48°35'25"

∠β =arcsin(b/c )

=arcsin(29.10326442171/44)

arcsin(0.66143782776615)

=0.72273 rad = 41.41° = 41°24'35"

h =a×b/c

=33 × 29.10326442171/44

=21.82745

area =a×b/2

=33 × 29.10326442171/2

=480.20386=363√7/2

perimeter =a+b+c

=33 + 29.10326442171 + 44

=106.10326

inradius =a×b/a+b+c

=960.40772591645/106.10326442171

=9.05163

circumradius =c/2

=44/2

=22

IRINA_888 [86]3 years ago

6 0

Answer:

im gonna go with 11 units^2

Step-by-step explanation:

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