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Svetradugi [14.3K]
4 years ago
11

75% of what number is 105?_____

Mathematics
2 answers:
Natalija [7]4 years ago
8 0
OK  so you want to convert 105 in percent or 75% in a whole number
luda_lava [24]4 years ago
7 0
Hope the shown work helps you!

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In the 1970s, due to world events, there was a gasoline shortage in the United States. There were often long lines of cars waiti
Harman [31]

Answer:

A line of cars will be about 9650000 feet

Step-by-step explanation:

Simple:

9.65*1,000,000=9650000

Hope this Helps!

Stay Safe!

7 0
3 years ago
This table shows how long, in minutes, it takes Jeremiah to run his miles.
sashaice [31]

Answer:

45

Step-by-step explanation:

follow the table of 9.

9x2=18

9x3=27

9x4=36

<u>9x5=45</u>

4 0
3 years ago
Determine the exact formula for the following discrete models:
marshall27 [118]

I'm partial to solving with generating functions. Let

T(x)=\displaystyle\sum_{n\ge0}t_nx^n

Multiply both sides of the recurrence by x^{n+2} and sum over all n\ge0.

\displaystyle\sum_{n\ge0}2t_{n+2}x^{n+2}=\sum_{n\ge0}3t_{n+1}x^{n+2}+\sum_{n\ge0}2t_nx^{n+2}

Shift the indices and factor out powers of x as needed so that each series starts at the same index and power of x.

\displaystyle2\sum_{n\ge2}2t_nx^n=3x\sum_{n\ge1}t_nx^n+2x^2\sum_{n\ge0}t_nx^n

Now we can write each series in terms of the generating function T(x). Pull out the first few terms so that each series starts at the same index n=0.

2(T(x)-t_0-t_1x)=3x(T(x)-t_0)+2x^2T(x)

Solve for T(x):

T(x)=\dfrac{2-3x}{2-3x-2x^2}=\dfrac{2-3x}{(2+x)(1-2x)}

Splitting into partial fractions gives

T(x)=\dfrac85\dfrac1{2+x}+\dfrac15\dfrac1{1-2x}

which we can write as geometric series,

T(x)=\displaystyle\frac8{10}\sum_{n\ge0}\left(-\frac x2\right)^n+\frac15\sum_{n\ge0}(2x)^n

T(x)=\displaystyle\sum_{n\ge0}\left(\frac45\left(-\frac12\right)^n+\frac{2^n}5\right)x^n

which tells us

\boxed{t_n=\dfrac45\left(-\dfrac12\right)^n+\dfrac{2^n}5}

# # #

Just to illustrate another method you could consider, you can write the second recurrence in matrix form as

49y_{n+2}=-16y_n\implies y_{n+2}=-\dfrac{16}{49}y_n\implies\begin{bmatrix}y_{n+2}\\y_{n+1}\end{bmatrix}=\begin{bmatrix}0&-\frac{16}{49}\\1&0\end{bmatrix}\begin{bmatrix}y_{n+1}\\y_n\end{bmatrix}

By substitution, you can show that

\begin{bmatrix}y_{n+2}\\y_{n+1}\end{bmatrix}=\begin{bmatrix}0&-\frac{16}{49}\\1&0\end{bmatrix}^{n+1}\begin{bmatrix}y_1\\y_0\end{bmatrix}

or

\begin{bmatrix}y_n\\y_{n-1}\end{bmatrix}=\begin{bmatrix}0&-\frac{16}{49}\\1&0\end{bmatrix}^{n-1}\begin{bmatrix}y_1\\y_0\end{bmatrix}

Then solving the recurrence is a matter of diagonalizing the coefficient matrix, raising to the power of n-1, then multiplying by the column vector containing the initial values. The solution itself would be the entry in the first row of the resulting matrix.

5 0
3 years ago
Evaluate 5x^2 + 2 for x = -1.
iogann1982 [59]

Answer:

7

Step-by-step explanation:

If x = -1 then we need to plug that into the equation.

5(-1)^2 +2

Then solve for the first part

5(1) + 2

Then multiply.

5 + 2

Then add

7.

Hope this helped!

6 0
3 years ago
Read 2 more answers
Latisha earns $5 an hour painting her neighbor's fence.
mario62 [17]
1 Hour = $5 OR H =$5
4 0
3 years ago
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