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Ilia_Sergeevich [38]
3 years ago
12

Solve the inequality. 2(4 + 2x) ≥ 5x + 5? x ≤ ?

Mathematics
2 answers:
NikAS [45]3 years ago
5 0
2(4+2x)≥5x+5
4+2x≥5/2x+5/2 (divide both sides by 2)
3/2+2x≥5/2x (subtract 5/2 from both sides)
3/2≥1/2x (subtract 2x from both sides)
3≥x (multiply both sides by 2)
or x≤3

Hope this helps
vichka [17]3 years ago
4 0
Solving for x     ( 2(4+2x) <span>≥ </span>5x +5  )
Answer would be
x ≤ 3

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==========================================================

Explanation:

We'll need to compute h(f(x)) and f(h(x)) to see if we get x each time.

h(x) = 9x-4\\\\h(f(x)) = 9(f(x))-4\\\\h(f(x)) = 9\left(\frac{x+4}{9}\right)-4\\\\h(f(x)) = x+4-4\\\\h(f(x)) = x\\\\

and,

f(x) = \frac{x+4}{9}\\\\f(h(x)) = \frac{h(x)+4}{9}\\\\f(h(x)) = \frac{9x-4+4}{9}\\\\f(h(x)) = \frac{9x}{9}\\\\f(h(x)) = x\\\\

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Step-by-step explanation:

f(x)=x^4-8x-11

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f(-4)=(-4)^4-8(-4)-11=(-4)(-4)(-4)(-4)+32-11=(16)(16)+32-11=256+32-11=288-11=277

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