If UT is the midsegment of QRS, then SQ = 2(2x + 2) = 4x + 4
Then,
(3x + 1)/(7x - 1) = (2x + 2)/(4x + 4) = 1/2
2(3x + 1) = 7x - 1
6x + 2 = 7x - 1
7x - 6x = 2 + 1
x = 3
Therefore, SQ = 4(3) + 4 = 12 + 4 = 16.
Answer:
4 boys
Step-by-step explanation:

3 × y = 1 × 12
3y = 12
3y ÷ 3 = 12 ÷ 3
y = 4
We know that the area of a circle has the formula A=πr²
We are given the diameter, and as we know that the diameter is twice the radius, we can divide the given diameter by 2.
27 ÷ 2= 13.5
Now, plug-in the number into the formula.
A=πr²
A=π×13.5²
A=π×182.25
(Assume π=3.14)
A=3.14 × 182.25
A=572.265
A=572.3 square meters.
Therefore, the area of the circle is 572.3 square meters.
1. reduce the fraction and subtract the exponents
(5x^7y^2)/2