Δ = 1 + 4*20 = 81
x' = (-1 + 9)/2 = 4
x'' = (-1 - 9)/2 = -5
4² + 4 - 20 = 0
(-5)² - 5 - 20 = 0
Ok !
we know that
The measure of the external angle is the semidifference of the arcs that it covers
so
∠MLN=(1/2)*(mayor arc MN-minor arc MN)
Let
x------> minor arc MN
major arc MN=360-x
substitute in the formula above
∠MLN=(1/2)*(mayor arc MN-minor arc MN)
75.86=(1/2)*(360-x-x)------> 151.72=(360-2x)------>360-151.72=2x
x=104.14°
therefore
the answer is
the measure of arc MN (minor arc) is 104.14°
2/3=14/21 and 5/7=15/21 so 14/21+15/21=29/21 or 1 and 8/21
Answer:
a= c/2
b= (c/2)×√3
side b is the side with the 60 degree angle.
side a is the side with the 30 degree angle.
using the theorem that the side with the 60 degree × 2 = length of side c and the side with the 60 degree × √3 = b.
I get the following equations shown above.
Answer: I got an eqaution I hope it is basic
Step-by-step explanation:
4 times 9
9 - (-3 ) times -9 + 5
