Answer:
Option D. w + x = z
Step-by-step explanation:
see the attached figure to better understand the problem
we have
----> equation A
----> equation B
equate equation A and equation B
Subtract y both sides
This equation satisfy the <em><u>Triangle Exterior Angle Theorem</u></em> (An exterior angle of a triangle is equal to the sum of the opposite interior angles)
A square pyramid has 4 triangles and the square base.
Calculate the area of one triangle, multiply that by 4 then add the area of the base.
Area of triangle = 1/2 x base x height = 1/2 x 5 x 12 = 30 square yards.
30 x 4 = 120 square yards
Area of base = 5 x 5 = 25 square yards
Total = 120 + 25 = 145 square yards.
x+2 > 10 solves to x > 8 after we subtract 2 from both sides
So set A is the set of real numbers that are larger than 8. The value 8 itself is not in set A. The same can be said about 5 as well.
Set B is the set of values that are larger than 5 since 2x > 10 turns into x > 5 after dividing both sides by 2. The value x = 5 is not in set B since x > 5 would turn into 5 > 5 which is false. The values x = 6, x = 8, and x = 9 are in set B.
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Summarizing everything, we can say...
5 is not in set A. True
5 is in set B. False
6 is in set A. False
6 is not in set B. False
8 is not in set A. True
8 is in set B. True
9 is in set A. True
9 is not in set B. False
Answer:5in
Step-by-step explanation:
1. Identify the triangle
you are given a right triangle with the hypotonus missing and are given the side lengths 3 and 4 you know the hypotonus is 5 by the 3,4,5 Pythagorean tripe, if you do not notice this it can be solved with the Pythagorean theorem a^2+b^2=c^2
2. solve (if not done with 3,4,5 triple)
3^2+4^2=c^2
9+16=c^2
25=c^2
5=c | square root both sides to cancel the square
Well, you have the radius and the center already. So all you have to do is graph the center point, then count from that center point out 5 units, then draw the circle.
