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3 years ago

As the Sun ages, what will happen to life here on Earth? Why?

1 answer:

3 0

Our Sun will slowly get hotter as more and more Helium accumulates in the Sun's core. In ~1 billion years, liquid water will no longer be possible on Earth's surface, and the oceans will completely boil away, resulting in a Venus-like planet. Only thermophyllic bacteria may be able to survive, perhaps at the poles. In ~4-5billion years, our Sun will have converted ~10% of its Hydrogen to Helium, and thus become so hot that Helium to Carbon fusion will begin in earnest, causing the "Helium flash" which will convert our Sun into a red giant, and swallow and vaporize all of the rocky inner planets. It may even blow off a planetary nebula. (Contrary to what the others have said, our Sun will not 'run out' of Hydrogen.)

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Zach run faster than abby his mass is 62 kg and he uses 372n how does he accelerate

murzikaleks [220]

Answer:

Acceleration, a = 6m/s²

Explanation:

Given the following data;

Mass = 62kg

Force = 372N

To find his acceleration;

Force is given by the multiplication of mass and acceleration.

Mathematically, Force is;

$F = ma$

Where;

F represents force.
m represents the mass of an object.
a represents acceleration.

Making acceleration (a) the subject, we have;

$Acceleration, a = \frac{F}{m}$

Substituting into the equation, we have;

$Acceleration, a = \frac{372}{62}$

Acceleration, a = 6m/s²

Therefore, Zach accelerates at the rate of 6 meters per seconds square.

4 0

3 years ago

Question 19

Valentin [98]

Answer:

Explanation:

3 0

3 years ago

Read 2 more answers

what do you call the activities of selecting and describing one or more target markets and developing and maintaining a market m

marissa [1.9K]

Answer:Marketing strategy involves the activities of selecting and describing one or more target markets and developing and maintaining a marketing mix that will produce mutually satisfying exchanges with target markets.

Explanation:

6 0

3 years ago

9*B

jonny [76]

Answer:

a. The bug is moving at a constant speed of -2 m/s

b. The total distance traveled by the bug is 17 meters

c. The distance the bug end up from its starting point is 3 meters

d. i. The bugs velocity is 0 when t = 0, 5, or 10 seconds,

ii. The bugs velocity is > 0 at 5 ≤ t ≤ 10

iii. The bugs velocity is < 0 at 0 ≤ t ≤ 5

e. i. The bug's acceleration is 0 at 2 ≤ t ≤ 4

ii. The bug's acceleration is > 0 at 4 ≤ t ≤ 6 and 8 ≤ t ≤ 9

iii. The bug's acceleration is > 0 at 0 ≤ t ≤ 2 and 9 ≤ t ≤ 10

f. The time the bug passes the starting point is approximately 8.83 seconds

Explanation:

a. When 2 ≤ t ≤ 4, the bug is moving at a constant speed of -2 m/s

b. The total distance the bug traveled is given by the area under the velocity-time graph which consist of two trapezoid and a triangle and is therefore is given as follows;

The area of the first (negative) trapezoid = -2 × (2 + 5)/2 = -7

The area of the second trapezoid = 2 × (3.5 + 5)/2 = 8.5

The area of the triangle = 1/2 × 1.5 × 2 = 1.5

The sum of the magnitude of the areas = The total distance traveled by the bug = $\left | -7 \right |$ + 8.5 + 1.5 = 17

The total distance traveled by the bug = 17 meters

c. The distance the bug end up from its starting point is given by the sum of the displacement (total displacement) of the bug

The total displacement of the bug = -7 + 8.5 + 1.5 = 3

The distance the bug end up from its starting point = The total displacement of the bug = 3 meters

d. i. The bugs velocity is 0 when the graph crosses the time, 't', axis, which is at points for time, t = 0 seconds, t = 5 seconds, and t = 10 seconds

ii. The bugs velocity is > 0 between the times, 5 ≤ t ≤ 10

iii. The bugs velocity is < 0 between the times, 0 ≤ t ≤ 5

e. i. The bug's acceleration is 0 between the times, 2 ≤ t ≤ 4

ii. The bug's acceleration is > 0 between the times, 4 ≤ t ≤ 6 and 8 ≤ t ≤ 9

iii. The bug's acceleration is > 0 between the times, 0 ≤ t ≤ 2 and 9 ≤ t ≤ 10

f. The bug passes the starting point at the time, 8 + t, where 't', is given by the area of a trapezoid as follows;

2 = t × (2 + 2 + t)/2

∴ 4 = 4·t + t²

t² + 4·t - 4 = 0

(t + (2 + 2·√2))·(t - (2·√2 - 2))

∴ t = 2·√2 - 2

The time the bug passes the starting point = 8 + 2·√2 - 2 = 6 + 2·√2 ≈ 8.83

The time the bug passes the starting point ≈ 8.83 seconds

4 0

3 years ago

Concurrent powers have which of the following effects on the United States political system?

AnnZ [28]

1. They make it possible for the states and the national government to simultaneously exercise influence in the same areas of public policy.

2. Strengthening anti-discrimination policies for married *** couples

3. An individual takes a civics course in school and develops opinions about politics.

4. To get a truly random sample

5. The questions contained a difference in wording.

6. The poll reported a sampling error.

5 0

3 years ago