Answer: SERIES = 670 Ω
PARALLEL = 91.94 Ω
Step-by-step explanation:
Hi, resistors in series obey the following equation :
R1+ R2 = RT
RT is the equivalent resistance. We have the value of both resistances, so we apply the ecuation:
R1 = 110Ω, and R2 = 560Ω
110Ω+ 560Ω = 670 Ω
When resistors are in parallel, resistors obey the following equation:
1/R1 + 1/R2= 1/RT
so, in our case:
1/ 110Ω +1/560Ω = 1/rt
0.01087Ω = 1/RT
RT= 1/0.01087 Ω= 91.94 Ω
Hopefully this helped you :)
Answer: 4a^2-2b^2 (I think this is right)
Step-by-step explanation:
Using the order of operations I started by multiplying both of the sides separately. The left side of the equation becomes 2a^2-b^2-ab while the right becomes 2a^2-b^2+ab. Then I put the sides together to add them and after combining like terms it becomes 4a^2-2b^2.
12,13,14,15,16,1 is the six values
Answer:
Jug B can hold 2340 ml.
Step-by-step explanation:
Given
The amount in Jug A = 1800ml
To determine
How much does jug B hold?
Give that the Jug B holds 3/10 more, i.e.
Thus,
The total amount in Jug B = 540+1800
= 2340 ml
Therefore, Jug B can hold 2340 ml.
