I have attached a screenshot with the images of the two popcorn bags used by the theater.
Part (a):Bag A:Volume of bag = area of base * height
Volume of bag = length * width * height
We have:
volume = 96 in³
length = 3 in
width = 4 in
Therefore:
96 = 3 * 4 * height
96 = 12 * height
height of bag A = 8 inBag B:Volume of bag = area of base * height
Volume of bag = length * width * height
We have:
volume = 96 in³
length = 4 in
width = 4 in
Therefore:
96 = 4 * 4 * height
96 = 16 * height
height of bag B = 6 inPart (b):To determine the amount of paper needed, we will need to calculate the surface of each bag. Excluding the top base, each bag will have 5 faces. Four side faces (each two opposite are equal) and the base.
Bag A:Surface area = area of base + 2*area of front face + 2*area of side face
Surface area = (3*4) + 2(8*4) + 2(8*3)
Surface area = 12 + 64 + 48
Surface area of bag A = 124 in²Bag B:Surface area = area of base + 2*area of front face + 2*area of side face
Surface area = (4*4) + 2(6*4) + 2(6*4)
Surface area = 16 + 48 + 48
Surface area of bag B = 112 in²From the above calculations, we can deduce that
the theater should choose bag B in order to reduce the amount of paper needed.
Hope this helps :)
The answer is
2
Explanation
You have to do 2/3 x 3 and you do that by multiplying 2 and 3 (6/6)
Which if you split up is 3/3, 3/3 = 2
Answer:
x = 14.25
Step-by-step explanation:
Start with a^2 + b^2 = c^2
a = 11
b = x
c = 18
plug in and solve
11^2 + x^2 = 18^2
121 + x^2 = 324 - Simplify
x^2 = 203 - subtract 121 from both sides
x = 14.247 rounds to 14.25 - square root on both sides
Answer:
3/4 of an hour
Step-by-step explanation:
To find the leftover time, subtract the total allotted time by the time used.
First make sure they have common denominators.
1 1/2 = 3/2 = 6/4
6/4 - 3/4 = 3/4
Tessa has 3/4 of an hour left.