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2 years ago

In a class full of men and women 5/9of the class are women. What is the ratio of men to women in its

Mathematics

1 answer:

Murljashka [212]2 years ago

4 0

Answer:

The ratio in its simplest from is 4:5

Step-by-step explanation:

Now, let’s pick an arbitrary value for the total number of students in that class.

Let’s say we have 45 students in the class

The number of women would be 5/9 * 45 = 25

The number of men would be 45-25 = 20

So the ratio of men to women would be;

20:25 which in its simplest form = 4:5

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After a storm, 135 trees out of 180 were left standing. What is the percentage loss of the number of trees?

beks73 [17]

Answer:

Percentage loss of the number of trees is $25\%$ .

Step-by-step explanation:

Given: After a storm, $135$ trees out of $180$ were left standing.

To find: What is the percentage loss of the number of trees?

Solution:

We have,

Total number of trees $=180$

Number of trees left standing $=135$

Therefore, loss of trees $=180-135=45$

We now that $\text {Loss\%}=\frac{\text{Number of trees left}}{\text{Total number of trees}}\times 100 \%$

$\implies \text {Loss\%}=\frac{45}{180}\times 100 \%$

$\implies \text {Loss\%}=\frac{450}{18} \%$

$\implies \text {Loss\%}=25 \%$

Hence, the percentage loss of the number of trees is $25\%$ .

6 0

2 years ago

Consider a line passing through the points A(–28, –13) and B(28, 15). Type the y-value for the point C(–24, y) to ensure that po

Nostrana [21]

Step-by-step explanation:

$\frac{y_2-y_1}{x_2-x_1}=\frac{15-(-13)}{28-(-28)}\\=\frac{28}{2(28)}\\\therefore\ m=\frac{1}{2}\\\frac{y-y_1}{xl-x_1}=m]\\\frac{y+13}{x+28}=\frac{1}{2}\\2y+26=x+28\\2y=x+2\\ y=\frac{1}{2}x+1$

In order to find y for point C on AB, substitute point C in line equation if AB.

$y=\frac{1}{2}(-24)+1\\\therefore y=-12+1=11\\\therefore C(-24, -11)$

7 0

2 years ago

A cat had a litter of 5 kittens. If each sex is equally likely, what is the probability that 3 or less were female kittens?

ASHA 777 [7]

Answer:

0.8125

Step-by-step explanation:

In this question, we are tasked with calculating the probability that 3 or less of her kittens were female.

Since each bsex is of likely probability, the probability of a male kitten = probability of a female kitten = 0.5

Now to calculate for 3 or less female kitten we are calcualting P(f) ≤ 3

In each case, we use the Bernoulli approximation

P(f) ≤ 3 = $5C3 m^{2} f^{3} + 5C2 m^{2} f^{3} + 5C1 m^{4} f + 5C0 m^{5} f^{0}$

Where m is the probability of a male kitten and f is the probability of having a female kitten with both values = 0.5

P(f) ≤ 3 =(0.3125) + (0.3125) + (0.15625) + (0.03125) = 0.8125

8 0

2 years ago

A dentist has male and female patients that range in ages from 10

marin [14]

Answer:

56/125

Step-by-step explanation:

7 0

2 years ago

A) - 17 B B)7 4. 3591 C) | D 12

vladimir1956 [14]

Answer:

Step-by-step explanation:

8 0

2 years ago