Evaluate the expression 3.14(a2 + ab) when a = 3 and b = 4. (Input decimals only, such as 12.71, as the answer.)

What is the inverse of f(x)=(x+6)2 for x≥–6 where function g is the inverse of function f?

alexdok [17]

Answer:

Sorry my mistake, it is actually worded as "f(x) =(x+6)^2"

Explanation:

y

=

(

x

+

6

)

2

with

x

≥

−

6

, then

x

+

6

is positive, so

√

y

=

x

+

6

And

x

=

√

y

−

6

for

y

≥

0

So the inverse of

f

is

g

(

x

)

=

√

x

−

6

for

x

≥

0

8 0

3 years ago

Read 2 more answers

A bag contains 6 red, 8

Virty [35]

8/26+12/26=20/26
So the probability for picking a green or blue marble is 20/26
10/13

5 0

3 years ago

What is the most common denomonator outof 1/3 1/5

Jlenok [28]

Answer:

1/5

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

7. Represent 56 + x = 7 using subtraction. What is x? Explain your<br> reasoning

Pie

Answer: 8

Step-by-step explanation: 7 X 8 = 56

5 0

3 years ago

Read 2 more answers

I need help please, I am so confused.

vazorg [7]

Answer:

$\begin{tabular}{| c | c | c |}\cline{1-3} Equation & x-intercepts & x-coordinate of vertex\\\cline{1-3} $y=x(x-2)$ & $x=0, x=2$ & $x=1$\\\cline{1-3} $y=(x-4)(x+5)$ & $x=-5, x=4$ & $x=-0.5$\\\cline{1-3} $y=-5x(x-3)$ & $x=0, x=3$ & $x=1.5$\\\cline{1-3} \end{tabular}$

Step-by-step explanation:

x-intercepts are when the curve intercepts the x-axis, so when y =0.

Therefore, to find the x-intercepts, substitute y = 0 and solve for x.

The vertex is the turning point: the minimum point of a parabola that opens upward, and the maximum point of the parabola that opens downward. As a parabola is symmetrical, the x-coordinate of the vertex is the midpoint of the x-intercepts.

Equation: $y=x(x-2)$

$\implies x(x-2)=0$

$\implies x=0$

$\implies (x-2)=0 \implies x=2$

Therefore, the x-intercepts are x = 0 and x = 2

The midpoint of the x-intercepts is x = 1, so the x-coordinate of the vertex is x = 1

Equation: $y=(x-4)(x+5)$

$\implies (x-4)(x+5)=0$

$\implies (x-4)=0 \implies x=4$

$\implies (x+5)=0 \implies x=-5$

Therefore, the x-intercepts are x = -5 and x = 4

The midpoint of the x-intercepts is x = -0.5, so the x-coordinate of the vertex is x = -0.5

Equation: $y=-5x(3-x)$

$\implies -5x(3-x)=0$

$\implies -5x=0 \implies x=0$

$\implies (3-x)=0 \implies x=3$

Therefore, the x-intercepts are x = 0 and x = 3

The midpoint of the x-intercepts is x = 1.5, so the x-coordinate of the vertex is x = 1.5

$\begin{tabular}{| c | c | c |}\cline{1-3} Equation & x-intercepts & x-coordinate of vertex\\\cline{1-3} $y=x(x-2)$ & $x=0, x=2$ & $x=1$\\\cline{1-3} $y=(x-4)(x+5)$ & $x=-5, x=4$ & $x=-0.5$\\\cline{1-3} $y=-5x(x-3)$ & $x=0, x=3$ & $x=1.5$\\\cline{1-3} \end{tabular}$

4 0

2 years ago