Answer:
x=1/2y+2
y=2x-4
Explanation:
For x-intercept:
4x-2y=8
-> subtract -2y on both sides
4x=2y+8
-> divide 4 on both sides to isolate the x
x=1/2y+2
For y-intercept:
4x-2y=8
-> subtract 4x on both sides
-2y=-4x+8
-> divide -2 on both sides to isolate the y
y=2x-4
Answer:
0.25
Explanation:
Since line AB = 5*sq root of 2, that tells us triangle ADB is an isoceles right triangle with legs=5. Therefore, triangle ACD is also an isoceles right triangle and so angle ACD (or B) = 45 degrees. One radian = 180/pi or 57.2958. Therefore angle ACB in radians is 45/57.2958 = .7854 = H*Pi. So H = .7854 / Pi = .7854 / 3.14159 = .0.25
So using a(2)=0 we can first solve for k by substituting t for 2
0 = (2-k)(2-3)(2-6)(2+3)
0 = (2-k)(-1)(-4)(5)
0 = (2-k)20
0 = 40 - 20k
-40 = -20k
k = 2
The next step would be to find all the 0s of a.
0 = (t-2)(t-3)(t-6)(t+3)
T = 2,3,6,-3
Then we find the product
2x3x6x-3 = -108
Since the problem asks for the absolute value, the answer is positive 108
