Answer:
<h2><em><u>2x</u></em><em><u> </u></em><em><u>×</u></em><em><u> </u></em><em><u>2x</u></em><em><u> </u></em><em><u>×</u></em><em><u> </u></em><em><u>2x</u></em></h2>
Step-by-step explanation:

= <em><u>2x × 2x × 2x (In expanded notation form) (Ans)</u></em>
Answer:
customary system:
miles
ounces
metric system:
deciliters
kilometers
centigram
Step-by-step explanation:
Here's what I got for the first question.
Did you want answers for the second one? I couldn't read that part of the image very well, if you did.
Answer:
(a) If r is any rational number and s is any irrational number, then r/s is rational
(b) The statement is false when r is 0
Step-by-step explanation:
Given
rational number
irrational number
irrational number
Solving (a): The negation
To get the negation of a statement, we only need to negate the end result
In other words, the number type of r and s will remain the same, but r/s will be negated.
So, the negation is:
rational number
irrational number
rational number
Solving (b): When r/s is irrational is false
Given that:
irrational number
Set r to 0
So:

-- rational
<em>Hence, the statement is false when r is 0</em>
This is not answer but Photomath is really helpful and it shows you step by step on how to solve it as well