Answer: The required probability of selecting 1 red apple and 2 yellow apples is 36.36%.
Step-by-step explanation: We are given that a bag contains 6 red apples and 5 yellow apples out of which 3 apples are selected at random.
We are to find the probability of selecting 1 red apple and 2 yellow apples.
Let S denote the sample space for selecting 3 apples from the bag and let A denote the event of selecting 1 red apple and 2 yellow apples.
Then, we have

Therefore, the probability of event A is given by

Thus, the required probability of selecting 1 red apple and 2 yellow apples is 36.36%.
Answer:
1/6
Step-by-step explanation:
using this formula

You get 0.1666666666666666666666666666666666666666
which is 1/6
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How is anyone supposed to answer this?
The variance of the binomial distribution of the number of households with landline service is 2.
<h3>What is the binomial probability distribution?</h3>
It is the probability of <u>exactly x successes on n repeated trials, with p probability</u> of a success on each trial.
The variance of the distribution is given by:
V(X) = np(1 - p)
In this problem, the parameters are given as follows:
n = 8, p = 0.504.
Hence the variance is given by:
V(X) = 8 x 0.504 x 0.496 = 2.
More can be learned about the binomial distribution at brainly.com/question/24863377
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