Answer:
1) (2x + 2)(x + 2)
2) 2(x + 1)(x - 1)
3) (x^2 + 3)(x^2 - 3)
4) 2x(x + 5)(x - 2)
5) (5x + 2y)(5x - 2y)
Step-by-step explanation:
1)
2x^2 + 6x + 4
= 2x^2 + 4x + 2x + 4
= 2x(x + 2) + 2(x + 2)
= (2x + 2)(x + 2)
2)
2x^2 - 2
= 2(x^ 2 - 1) (The difference of two squares)
= 2(x + 1)(x - 1)
3)
x^4 - 9 (The difference of two squares)
=(x^2 + 3)(x^2 - 3)
4)
2x^3 + 6x^2 - 20x
= 2x(x^2 + 3x - 10)
= 2x(x + 5)(x - 2)
5)
25x^2 - 4y^2 (The difference of two squares)
= (5x + 2y)(5x - 2y)
Answer:
Step-by-step explanation:
1) we have to find the area of the cut out portion
Since both circles in one side makes up the side 28cm
The diameter of each circle is 14cm
radius = diameter / 2
r = 7cm
Area of a circle = πr²
A = 22/7 × 7²
= 22/7 × 7 × 7
= 22 × 7 = 154cm²
So the four circles will make
= 154 + 154 + 154 + 154
= 616 cm²
The Area of the square will be
= L × L
= 28 × 28
= 784 cm²
Therefore the area of the remaining portion will be
Area of the square - total area of the circles
= 784 cm² - 616 cm²
= 168 cm²
The area of the remaining part is 168 cm²
Answer:
If it is a 6 sided dice, then the probability will be roughly a 1 in 12 chance
Step-by-step explanation:
I think, not entirely sure, sorry if it is wrong
