Answer:
<em>Thus, the dimensions of the metal plate are 10 dm and 8 dm.</em>
Step-by-step explanation:
For a quadratic equation:

The sum of the roots is -b and the product is c. Note the leading coefficient is 1.
We know the perimeter of the rectangular metal plate is 36 dm and its area is 80 dm^2. Being L and W its dimensions, then:
P=2(L+W)=36
A=L.W=80
Note both formulas are closely related to the roots of the quadratic equation, we only need to adjust the data for the perimeter to be exactly the sum of L+W and not double of it.
Thus we use the semi perimeter instead as P/2=L+W=18
The quadratic equation is, then:

Factoring by finding two numbers that add up to 18 and have a product of 80:

The solutions to the equation are:
x=10, x=8
Thus, the dimensions of the metal plate are 10 dm and 8 dm.
It’s nonporportiniol sorry if it’s spelled wrong lol
Answer: 
Step-by-step explanation:
Given
The unit cost is given by

find the derivative of the unit cost and equate it to zero to obtain the minimum value

Substitute 140 for
in the cost function, we get
![C(140)=0.6[140]^2-168(140)+30,389\\C(140)=11,760-23,520+30,389\\C(140)=\$18,629](https://tex.z-dn.net/?f=C%28140%29%3D0.6%5B140%5D%5E2-168%28140%29%2B30%2C389%5C%5CC%28140%29%3D11%2C760-23%2C520%2B30%2C389%5C%5CC%28140%29%3D%5C%2418%2C629)
36÷3=12 12×5=60(the area of the resulting triangle)