Solve each equation by using the square root property. 7x^2

twelve and three tenths more than five and thirteen thousandths of a number d is equal to fifteen and three hundred two thousand

AVprozaik [17]

5.013d + 12.3 = 15.302
5.013d = 15.302 - 12.3
5.013d = 3.002
d = 3.002 / 5.013
d = 0.599 (thats rounded) <==

6 0

3 years ago

Math question please help <br> If you get this right I will mark you as a brainliest

iogann1982 [59]

Much as you would like it to be D, it isn't. D has its center at (3,4). You must change the sign on both numbers inside the brackets.

You need something that looks like (x + 3)^2 + (y + 4)^2. So it could be A or B. How do you know which? The graph should give you an answer, then we'll talk about it. The red circle is A the blue circle is B. Which one is correct?

The answer to that is that the center is 5 units away from the origin. The radius of this circle is the sqrt(25) = 5 units away from the center. The blue one has a radius of sqrt(5) which is something over 2. It is not enough. So what's the answer?

4 0

4 years ago

Suppose that 30% of all students who have to buy a text for a particular course want a new copy (the successes!), whereas the ot

Softa [21]

Answer:

a. Mean = 4.5, Standard Deviation = 1.775

b. 0.0152

Step-by-step explanation:

Given

n = 15 purchasers

p = Success = 30%

p = 0.3

q =Failure = 70%

q = 0.7

a.

Mean = np

Mean = 15 * 0.3

Mean = 4.5

Standard Deviation = √Variance

Variance = npq

Variance = 15 * 0.3 * 0.7

Variance = 3.15

Standard Deviation = √3.15

Standard Deviation = 1.774823934929884

Standard Deviation = 1.775 ---------- Approximated

b.

The probability that the number who want new copies is more than two standard deviations away from the mean value

Standard Deviation = 1.775

Mean = 4.5

2 Standard Deviation and Mean = 2 * 1.775 + 4.5

= 3.55 + 4.5

= 8.05

P(X>8.05) = P(9) + P(10) +........+ P(15)

Using the binomial distribution

(p + q) ^ n where p = 0.3, q = 0.7 , n = 15

Expanding (p+q)^n where n = 15 and r > 8

We have

15C9 p^9 q^6 + 15C10 p^10 q^5 + 15C11 p^11 q⁴ + 15C12 p^12 q³ + 15C13 p^13 q² + 15C14 p^14 q + p^15

= 5005 (0.3)^9 (0.7)^6 + 3003 (0.3)^10 (0.7)^5 + 1365 (0.3)^11 (0.7)⁴ + 455 (0.3)^12 (0.7)³ + 105 (0.3)^14 (0.7)² + 15 (0.3)^14 (0.7) + 0.3^15

=0.015234

7 0

4 years ago

Please help me I don’t understand it’s number 2<br> 2. Select all the pairs that are<br> equivalent.

kenny6666 [7]

Answers 3 and 4! since there is a negative power, that’s the only time the 0’s are added to the front :)

6 0

3 years ago

Jar #3 contains 21 gummie bears. How many gummie bears can you get if you can have 1/3 of them

Vlada [557]

Answer:

7 gummy bears

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Solve each equation by using the square root property. 7x^2–17=39.