Question

Which equation, when graphed, has x-intercepts at (2, 0) and (4, 0) and a y-intercept of (0, –16)?

Answer 1

Assuming you want quadratic
when x=0, y=-16

y=ax^2+bx+c
-16=0+c
-16=c


when x=2, y=0
0=a(2)^2+2b-16
0=4a+2b-16
16=4a+2b
8=2a+b

when x=4, y=0
0=a(4)^2+4b-16
0=16a+4b-16
16=16a+4b
4=4a+b

we has 2 equations
8=2a+b
4=4a+b

multiply first by -1 and add to 2nd
-8=-2a-b
4=4a+b +
-4=2a+0b

-4=2a
-2=a
sub back

4=4a+b
4=4(-2)+b
4=-8+b
12=b


y=ax^2+bx+c
y=-2x²+12x-16

Answer 2

Answer:

y=-2x²+12x-16

Step-by-step explanation: