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Diano4ka-milaya [45]
4 years ago
6

Find x (2x+1) (5x+5)

Mathematics
2 answers:
mezya [45]4 years ago
8 0

explanation;

Solution for <em>2x+1=5x-5</em> equation

Simplifying

<em>2x + 1 = 5x + -5</em>

Reorder the terms:

<em>1 + 2x = 5x + -5</em>

Reorder the terms:

<em>1 + 2x = -5 + 5x</em>

Solving

<em>1 + 2x = -5 + 5x </em>

Solving for variable<em> 'x'. </em>

Move all terms containing x to the left, all other terms to the right.

Add <em>'-5x'</em> to each side of the equation.

<em>1 + 2x + -5x = -5 + 5x + -5x </em>

Combine like terms: <em>2x + -5x = -3x </em>

<em>1 + -3x = -5 + 5x + -5x </em>

Combine like terms: <em>5x + -5x = 0 </em>

<em>1 + -3x = -5 + 0 </em>

<em>1 + -3x = -5 </em>

Add '-1' to each side of the equation.

<em>1 + -1 + -3x = -5 + -1 </em>

Combine like terms: <em>1 + -1 = 0 </em>

<em>0 + -3x = -5 + -1 </em>

<em>-3x = -5 + -1 </em>

Combine like terms: <em>-5 + -1 = -6 </em>

<em>-3x = -6 </em>

Divide each side by <em>'-3'. </em>

<em>x = 2 </em>

Simplifying

<em>x = 2</em>

Korolek [52]4 years ago
6 0

Answer:

x=2

Step-by-step explanation:

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Step-by-step explanation:

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2 years ago
The density of ice is approximately 0.92 g/cm3 . If a block of ice has a volume of 2300 cm3, what is its mass?
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Answer:

The mass of the ice block is 2116 grams ⇒ a

Step-by-step explanation:

The formula of density is p=\frac{m}{V} , where m is the mass and V is the volume

To find the mass from this formula multiply both sides by V,

then m = p.V

∵ The density of ice is approximately 0.92 g/cm³

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- That means the mass of 1 cm³ is 0.92 g

∵ The volume of an ice block is 2300 cm³

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- Use the formula of the mass

∵ m = p.V

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Please help me with these questions , thank you​
Angelina_Jolie [31]

Answer:

1. 4x^{3} + 26x² + 4x - 48

2. 2x^{3} - 23x² + 60x - 32

3. x^{5} + 7x^{3} - 4x + 2x^{4} + 14x² - 8

4. 2x^{7} + x^{6} - 28x^{5} + 3x + 12

Step-by-step explanation:

To multiply polynomials, simply distribute whatever's outside the largest set of parenthesis, then combine like terms.

1) Distribute the parenthesis (x + 6):

x(4x² + 2x - 8)  +  6(4x² + 2x - 8)

4x^{3} + 2x² -8x  +  6(4x² + 2x -8)

4x^{3} + 2x² -8x + 24x² + 12x - 48

Combine like terms:

4x^{3} + 26x² + 4x - 48

2) Distribute the parenthesis (x - 8):

x(2x² - 7x + 4)  +  (-8)(2x² - 7x + 4)

2x^{3} - 7x² + 4x  +  (-8)(2x² - 7x + 4)

2x^{3} - 7x² + 4x  +  -16x² + 56x - 32

Combine like terms:

2x^{3} - 23x² + 60x - 32

3) Distribute the parenthesis (x + 2):

x(x^{4} + 7x² - 4)  +  2(x^{4} + 7x² - 4)

x^{5} + 7x^{3} - 4x  +  2(x^{4} + 7x² - 4)

x^{5} + 7x^{3} - 4x + 2x^{4} + 14x² - 8

No like terms to combine, so:

x^{5} + 7x^{3} - 4x + 2x^{4} + 14x² - 8

4) Distribute the parenthesis (x + 4):

x(2x^{6} - 7x^{5} + 3)  +  4(2x^{6} - 7x^{5} + 3)

2x^{7} - 7x^{6} + 3x  +  4(2x^{6} - 7x^{5} + 3)

2x^{7} - 7x^{6} + 3x + 8  x^{6} - 28x^{5} + 12

Combine like terms:

2x^{7} + x^{6} - 28x^{5} + 3x + 12

hope this helps!

8 0
3 years ago
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