Answer:
D) 11/3
Step-by-step explanation:
Let x represent monthly salary.
We have been given that for each month of a given year except December, a worker earned the same monthly salary and donated one-tenth of that salary to charity.
Salary earned in 11 months would be
.
Money donated in 11 months would be
.
Further we are told that in December, the worker earned N times his usual monthly salary and donated one-fifth of his earnings to charity.
Salary for December would be
.
Money donated in December would be
.
The worker's charitable contributions totaled one-eighth of his earnings for the entire year that is
.

Dividing whole equation by x, we will get:


Combine like terms:






Therefore, the value of N is 11/3 and option D is the correct choice.
Intersecting the x axis means y is 0
plug y=0 in the equation and solve for x to see if there are real solutions
x^2-10x+0+0=-30
x^2-10x+30=0
this cannot be factored, so let's see if b^2-4ac is bigger than 0
10^2-4*1*30=-20
so the solutions for this equation are not real numbers, therefore the answer is no.
1. rhombus
1. square
3. circle
dont actually use these answers im not 100%sure :)
Answer:
1.3333333333333333333333 TO INFINITY AND BEYOND.