The answer is False!
P - dominant allele for inflated pods
p - recessive allele for inflated pods
PP - homozygote with inflated pods
Pp - heterozygote with inflated pods
pp - homozygote with inflated pods
S - dominant allele for round seeds
s - recessive allele for wrinkled seeds
SS - homozygote with round seeds
Ss - heterozygote with round seeds
ss - homozygote with wrinkled seeds
1. <span>A Pea plant that is homozygous for inflated pods are heterozygous for round seeds: PPSs
2. A</span><span> plant that is heterozygous for inflated pods and a homozygous for wrinkled seeds: Ppss
Let's look at their genotypes separately, and cross them that way:
Parents: PP x Pp
Offspring: PP PP Pp Pp
All of the offspring will have the same phenotype (100% = 1). So, this trait does not affect phenotypic ratio
</span>Parents: Ss x ss
Offspring: Ss Ss ss ss
Half of the offspring will have wrinkled seeds and half of them will have round seeds: 50% : 50% = 1 : 1
So, the phenotypic ratio is not 1 : 3
The answer would be salt hydrolysis.
Salt that was made from the combination of weak and strong acid/base could be hydrolyzed and forming another substance. The hydrolysis process will separate the H2O into H+ and OH- and the weak part of the salt will take one of the ions(weak base will take OH-, weak acid will take H+). The result would be increased H+( or OH- ion, leading to change in pH of the solution.
Telophase II begins after the separation of sister chromatids. In this phase individual chromosomes reach at pole. Nuclear membrane starts getting formed around them and cytokinesis takes place. Cytokinesis is the division of cytoplasm.
This results in the formation of four daughter cells which are haploid.
