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zavuch27 [327]
3 years ago
13

Find m∠V. Struggling in geometry! Help plz :/

Mathematics
2 answers:
MAVERICK [17]3 years ago
7 0

Answer:

16 degrees

Step-by-step explanation:

74 + 90 = 164

180-164 = 16

Lana71 [14]3 years ago
5 0
The answer is 16.

Both triangles are congruent so that means Angle T is 74 degrees. There is also a right angle which means there is 90 degrees in that angle. A triangle always has 180 degrees so add 74+90 which is 164. Then subtract 180-164=16
Good luck :)
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PLZ HURRY Last question i need a good grade
NISA [10]

Answer:

C. The lines are perpendicular

Step-by-step explanation:

GO GET GOOD GrADE

4 0
2 years ago
If G is the midpoint of FH find FG<br>fg=11x-7 gh= 3x+9
gavmur [86]

Solution:

we are given that

If G is the midpoint of FH,  it mean that

FG=GH

we are also given that

FG=11x-7 ,GH= 3x+9

So we can write

11x-7=3x+9\\&#10;\\&#10;11x-3x=7+9\\&#10;\\&#10;8x=16\\&#10;\\&#10;x=2

So FG=11x-7=11*\frac{1}{2}-7=11*2-7=15


3 0
3 years ago
What is the answer and how do I solve it?
vichka [17]
The lengths of the rectangles are 7 and 12 respectively.  Form the ratio 7/12.  The widths of the rects. are x and 5 respectively.  Form the ratio x/5.  Now equate these two ratios:

7       x
--- = ---
12     5

Solve this for x.  One way to do this would be to cross-multiply, obtaining 12x = 35, and solving this result for x.  x will be a fraction.  Write the numerator and denominator in the boxes given.
4 0
3 years ago
Express the quotient of z1 and z2 in standard form given that <img src="https://tex.z-dn.net/?f=z_%7B1%7D%20%3D%20-3%5Bcos%28%5C
Lesechka [4]

Answer:

Solution : -\frac{3}{4}-\frac{3}{4}i

Step-by-step explanation:

-3\left[\cos \left(\frac{-\pi }{4}\right)+i\sin \left(\frac{-\pi \:}{4}\right)\right]\:\div \:2\sqrt{2}\left[\cos \left(\frac{-\pi \:\:}{2}\right)+i\sin \left(\frac{-\pi \:\:\:}{2}\right)\right]

Let's apply trivial identities here. We know that cos(-π / 4) = √2 / 2, sin(-π / 4) = - √2 / 2, cos(-π / 2) = 0, sin(-π / 2) = - 1. Let's substitute those values,

\frac{-3\left(\frac{\sqrt{2}}{2}-\frac{\sqrt{2}}{2}i\right)}{2\sqrt{2}\left(0-1\right)i}

=-3\left(\frac{\sqrt{2}}{2}-\frac{\sqrt{2}}{2}i\right) ÷ 2\sqrt{2}\left(0-1\right)i

= 3\left(-\frac{\sqrt{2}i}{2}+\frac{\sqrt{2}}{2}\right) ÷ -2\sqrt{2}i

= \frac{3\left(1-i\right)}{\sqrt{2}}÷ 2\sqrt{2}i = -3-3i ÷ 4 = -\frac{3}{4}-\frac{3}{4}i

As you can see your solution is the last option.

3 0
3 years ago
A group of college students are going to a lake house for the weekend and plan on renting small cars and large cars to make the
maxonik [38]

The students rented 4 small cars and 8 large cars.

Step-by-step explanation:

Given,

Number of people in small car = 4

Number of people in large car = 7

Total people in both type of cars = 72

Let,

x represent the number of small cars rented.

y represent the number of large cars rented.

According to given statement;

4x+7y=72     Eqn 1

y = 2x           Eqn 2

Putting value of y from Eqn 2 in Eqn 1

4x+7(2x)=72\\4x+14x=72\\18x=72

Dividing both sides by 18

\frac{18x}{18}=\frac{72}{18}\\x=4

Putting x=4 in Eqn 2

y=2(4)\\y=8

The students rented 4 small cars and 8 large cars.

Keywords: linear equation, substitution method

Learn more about linear equations at:

  • brainly.com/question/10557938
  • brainly.com/question/10600222

#LearnwithBrainly

3 0
3 years ago
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