Part A.
Ashwin had a 4-cm cube.
volume of cube = side^3
volume = (4 cm)^3 = 64 cm^3
Ashwin has 64 small cubes.
We need to find the volumes of all prisms in Part A. Only prisms with at most 64 cm^3 volume can be the answer.
A. v = 2 * 4 * 7 = 28
B. v = 4 * 5 * 6 = 120
C. v = 5 * 5 * 4 = 100
D. v = 4 * 7 * 5 = 140
E. v = 3 * 5 * 4 = 60
Part A. answer: A, E
Part B.
Dora had a 5-cm cube.
volume of cube = side^3
volume = (5 cm)^3 = 125 cm^3
Dora has 125 small cubes.
We need to find the volumes of all prisms in Part B. Only prisms with at most 125 cm^3 volume can be the answer.
A. v = 3 * 3 * 8 = 72
B. v = 3 * 4 * 5 = 60
C. v = 6 * 6 * 4 = 144
D. v = 5 * 8 * 4 = 160
E. v = 3 * 5 * 4 = 60
Part B. answer: A, B, E
Answer:
x=9 and y=115
Step-by-step explanation:
Solve y=9x+34;y=16x−29
Steps:
I will solve your system by substitution.
y=9x+34;y=16x−29
Step: Solvey=9x+34for y:
Step: Substitute9x+34foryiny=16x−29:
y=16x−29
9x+34=16x−29
9x+34+−16x=16x−29+−16x(Add -16x to both sides)
−7x+34=−29
−7x+34+−34=−29+−34(Add -34 to both sides)
−7x=−63
−7x
−7
=
−63
−7
(Divide both sides by -7)
x=9
Step: Substitute9forxiny=9x+34:
y=9x+34
y=(9)(9)+34
y=115(Simplify both sides of the equation)
Hope this helps :)
Answer:
56 units²
Step-by-step explanation:
Each triangle has an area that is ...
... A = 1/2bh = 1/2·7·4
There are 4 such triangles, so the total area is ...
... 4A = 4(1/2)·7·4 = 2·7·4 = 56 . . . . units²
_____
An area formula customarily used when the diagonals are pependicular to each other is that the area is half the product of their lengths.
... A = (1/2)d1·d2 = (1/2)·14·8 = 56
Is there a graph? not sure what to solve.
Answer:it is linear because every time x increases 1, y increases by 2.
Step-by-step explanation:it is a linear relationship and it is changing at a constant rate