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3 years ago

Lines a and b are parallel. What is the measure of ∠3 if ∠6 measures 84°?

Mathematics

2 answers:

Anon25 [30]3 years ago

7 0

Answer:

C) 84°

Step-by-step explanation:

Ray Of Light [21]3 years ago

4 0

Answer:

it also measures 84° because 3is alternate angle to 6

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Andru [333]

5d - 7 = -13
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d = -6/5

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What is the volume of the right rectangular prism?

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3 years ago

Read 2 more answers

Suppose the CPI has a value of 225.3 exactly one year ago, and the current value of this index is 231.16, a rise of 5.86 points.

sertanlavr [38]

Answer:

2.6%

Step-by-step explanation:

Given the current CPI = 231.56

Previous CPI (CPI a year ago) = 225.3

Rate of inflation over the past year = current CPI - previous CPI/previous CPI × 100%

Rate of inflation = 231.56-225.3/225.3 × 100%

5.86/225.3× 100%

= 2.6%

Rate of inflation over the past year will be 2.6%

4 0

3 years ago

For parts a and bâ, use technology to estimate the following. âa) The critical value of t for a 90â% confidence interval with df

rjkz [21]

Answer:

a) For the 90% confidence interval the value of $\alpha=1-0.9=0.1$ and $\alpha/2=0.05$ , with that value we can find the quantile required for the interval in the t distribution with df =3. And we can use the folloiwng excel code: "=T.INV(0.05,3)" and we got:

$t_{\alpha/2} =\pm 2.35$

b) For the 99% confidence interval the value of $\alpha=1-0.99=0.01$ and $\alpha/2=0.005$ , with that value we can find the quantile required for the interval in the t distribution with df =106. And we can use the folloiwng excel code: "=T.INV(0.005,106)" and we got:

$t_{\alpha/2} =\pm 2.62$

Step-by-step explanation:

Previous concepts

The t distribution (Student’s t-distribution) is a "probability distribution that is used to estimate population parameters when the sample size is small (n<30) or when the population variance is unknown".

The shape of the t distribution is determined by its degrees of freedom and when the degrees of freedom increase the t distirbution becomes a normal distribution approximately.

The degrees of freedom represent "the number of independent observations in a set of data. For example if we estimate a mean score from a single sample, the number of independent observations would be equal to the sample size minus one."

Solution to the problem

Part a

For the 90% confidence interval the value of $\alpha=1-0.9=0.1$ and $\alpha/2=0.05$ , with that value we can find the quantile required for the interval in the t distribution with df =3. And we can use the folloiwng excel code: "=T.INV(0.05,3)" and we got:

$t_{\alpha/2} =\pm 2.35$

Part b

For the 99% confidence interval the value of $\alpha=1-0.99=0.01$ and $\alpha/2=0.005$ , with that value we can find the quantile required for the interval in the t distribution with df =106. And we can use the folloiwng excel code: "=T.INV(0.005,106)" and we got:

$t_{\alpha/2} =\pm 2.62$

3 0

3 years ago

If the standard deviation of a data set were originally 12, and if each value in

Zanzabum

Answer: 21

Step-by-step explanation:

Take 12 and multiply it by 1.75 (12x1.75) and you’ll get 21

6 0

3 years ago