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Alexus [3.1K]
3 years ago
9

A student wants to find point C on the directed line segment from A to B on a number line such that the segment is partitioned i

n a ratio of 3:4. Point A is at -6 and point B is at 2. The student's work is shown .
Mathematics
2 answers:
Black_prince [1.1K]3 years ago
8 0

Answer:

the answer is A

No, the student should have added 3 + 4 to get the total number of sections, and used the fraction Three-sevenths

Step-by-step explanation:

olganol [36]3 years ago
7 0

Answer:

<u>Point C at (-18/7)</u>

Step-by-step explanation:

Point A is at -6 and point B is at 2.

So, the distance between A and B = 2 - (-6) = 8

point C on the directed line segment from A to B on a number line such that the segment is partitioned in a ratio of 3:4.

Let the distance AC = x

∴ BC = 8 - x

AC : CB = 3 : 4

∴\frac{AC}{CB} =\frac{3}{4} = \frac{x}{8-x}

Using cross multiplication

3 (8-x) = 4x

24 - 3x = 4x

24 = 7x

x = 24/7

So, Point C = -6 + 24/7 = -18/7

Point C at (-18/7)

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Answer:

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Step-by-step explanation:

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y = x^2 – 40x – 3,200,

0 = x^2 – 40x – 3,200,

x^2 – 40x – 3,200 = 0

x^2 – 80x  + 40x – 3,200 = 0

x(x-80)+40(x-80) = 0

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The explanation is shown below:

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Answer:

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