Hey there!
Even if there isn't anyone working on the circuit at the moment, it still may be exposed and activating it could cause a variety of problems. This means that whoever is present or whatever time you would activate the circuit is irrelevant as the switch should only be thrown after permission is given.
Logically, you would need permission from whoever ordered against throwing the switch in the first place, which should be the person who signed it. I believe that your answer will be "<span>Operate this switch only after getting permission from the person who signed the tag", which is D.
Hope this helped you out! :-)</span>
Answer:
The second print statement will print:
f2.i is 1 f2.s is 2
Explanation:
Initially when the execution start. i and s are both 0. i declared as a variable while s is a static variable which value stays once it is re-defined.
When f1 call i and s; their value is both 1 based on the increment statement in the constructor.
For the second print statement:
When f2 call i; it is re-initialized to 1. When f2 call s; it has initial value of 1 and is incremented to 2 which is printed. s hold the initial value of 1 because of the static keyword.
I don’t know xd I’m failing schooln
If Lucy wants to move data from column A to column N within the same worksheet, she needs to use the Ctrl + c and Ctrl + v keys. But before these key combination, she needs to select first the column A by merely clicking the column A, then ctrl+c and ctrl+v.
