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4 years ago

What is 5(x-5) simplified?

Mathematics

2 answers:

stepladder [879]4 years ago

8 0

Answer:10

Step-by-step explanation:

Dafna11 [192]4 years ago

8 0

5(x-5)

5x-25 hope this helps you

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$2.95+$3.09+$5.85+$4.10

Gnom [1K]

Step-by-step explanation:

the value of P(B|A)P(B∣A), rounding to the nearest thousandth

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3 years ago

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What is -1/9 + -5/7

Lerok [7]

Answer: 52/65

Make the denominator the same fraction and do for both numerator and denominator

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3 years ago

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1. WRUF 103.7 FM is giving away tickets to a concert. Tim, the general manager of the

Eva8 [605]

Answer:

Kindly check explanation

Step-by-step explanation:

Given that :

Upper level seat = $25

Mid level seat = $40

Number of tickets to give away is at least 25

Budget constraint = $1000

part A: write a system of two inequalities that describe this situation

Number of tickets constraint:

Upper level + mid level ≥ 25

u + m ≥ 25

Cost constraint :

$25u + $40m ≤ $1000

Part B:

Give away 10 upper level seat tickets and 15 mid level seat tickets

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3 years ago

I WILL GIVE BRAINLIST

Tatiana [17]

C I think pretty sure tho

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3 years ago

Determine all prime numbers a, b and c for which the expression a ^ 2 + b ^ 2 + c ^ 2 - 1 is a perfect square .

kogti [31]

Answer:

The family of all prime numbers such that $a^{2} + b^{2} + c^{2} -1$ is a perfect square is represented by the following solution:

$a$ is an arbitrary prime number. (1)

$b = \sqrt{1 + 2\cdot a \cdot c}$ (2)

$c$ is another arbitrary prime number. (3)

Step-by-step explanation:

From Algebra we know that a second order polynomial is a perfect square if and only if $(x+y)^{2} = x^{2} + 2\cdot x\cdot y + y^{2}$ . From statement, we must fulfill the following identity:

$a^{2} + b^{2} + c^{2} - 1 = x^{2} + 2\cdot x\cdot y + y^{2}$

By Associative and Commutative properties, we can reorganize the expression as follows:

$a^{2} + (b^{2}-1) + c^{2} = x^{2} + 2\cdot x \cdot y + y^{2}$ (1)

Then, we have the following system of equations:

$x = a$ (2)

$(b^{2}-1) = 2\cdot x\cdot y$ (3)

$y = c$ (4)

By (2) and (4) in (3), we have the following expression:

$(b^{2} - 1) = 2\cdot a \cdot c$

$b^{2} = 1 + 2\cdot a \cdot c$

$b = \sqrt{1 + 2\cdot a\cdot c}$

From Number Theory, we remember that a number is prime if and only if is divisible both by 1 and by itself. Then, $a, b, c > 1$ . If $a$ , $b$ and $c$ are prime numbers, then $2\cdot a\cdot c$ must be an even composite number, which means that $a$ and $c$ can be either both odd numbers or a even number and a odd number. In the family of prime numbers, the only even number is 2.