Answer: x³-2x²-5x-6=(x-1)*(x-3)*(x+2).
Step-by-step explanation:

Answer:
the maximum concentration of the antibiotic during the first 12 hours is 1.185
at t= 2 hours.
Step-by-step explanation:
We are given the following information:
After an antibiotic tablet is taken, the concentration of the antibiotic in the bloodstream is modeled by the function where the time t is measured in hours and C is measured in 

Thus, we are given the time interval [0,12] for t.
- We can apply the first derivative test, to know the absolute maximum value because we have a closed interval for t.
- The first derivative test focusing on a particular point. If the function switches or changes from increasing to decreasing at the point, then the function will achieve a highest value at that point.
First, we differentiate C(t) with respect to t, to get,

Equating the first derivative to zero, we get,

Solving, we get,

At t = 0

At t = 2

At t = 12

Thus, the maximum concentration of the antibiotic during the first 12 hours is 1.185
at t= 2 hours.
Answer:
PT and SQ
Step-by-step explanation:
IF two segments are perpendicular then they will create 90 degree angles
segment PR and segment SQ cross over each other and create 90 degree angles therefore segment PR is perpendicular to segment SQ
A.) For the Junior Varsity Team, mean would be the appropriate measure of center since the data is <span>symmetric or well-proportioned while we should use standard deviation for getting the measure of spread since it also measures the center and how far the values are from the mean.
b.) For the Varsity Team, the median would be the appropriate measure of the center since the data is skewed left and not evenly distributed so median could be used since it does not account for outliers while we use IQR or interquartile range in measuring the spread of data since IQR does not account for the data that is skewed. </span>
The volume is 336 cubic feet
6x8x3 = 144
8x4x6= 192
144+192=336