Remember: We have to work from either the LHS or the RHS.
(Left hand side or the Right hand side)
You should already know this:
![\huge{Cot(t) = \frac{1}{tan(t)} = \frac{1}{\frac{sin(t)}{cos(t)}} = 1\div \frac{sin(t)}{cos(t)} = 1\times \frac{cos(t)}{sin(t)}=\boxed{\frac{cos(t)}{sin(t)}}](https://tex.z-dn.net/?f=%5Chuge%7BCot%28t%29%20%3D%20%5Cfrac%7B1%7D%7Btan%28t%29%7D%20%3D%20%5Cfrac%7B1%7D%7B%5Cfrac%7Bsin%28t%29%7D%7Bcos%28t%29%7D%7D%20%3D%201%5Cdiv%20%5Cfrac%7Bsin%28t%29%7D%7Bcos%28t%29%7D%20%3D%201%5Ctimes%20%5Cfrac%7Bcos%28t%29%7D%7Bsin%28t%29%7D%3D%5Cboxed%7B%5Cfrac%7Bcos%28t%29%7D%7Bsin%28t%29%7D%7D)
You should also know this:
![sin^2(t) + cos^2(t) = 1\\\\\boxed{sin^2(t)} = 1 - cos^2(t)](https://tex.z-dn.net/?f=sin%5E2%28t%29%20%2B%20cos%5E2%28t%29%20%3D%201%5C%5C%5C%5C%5Cboxed%7Bsin%5E2%28t%29%7D%20%3D%201%20-%20cos%5E2%28t%29)
So plugging in both of those into our identity, we get:
![\frac{cos(t)}{sin(t)}\cdot sin^2(t) = cos(t)\cdot sin(t)](https://tex.z-dn.net/?f=%5Cfrac%7Bcos%28t%29%7D%7Bsin%28t%29%7D%5Ccdot%20sin%5E2%28t%29%20%3D%20cos%28t%29%5Ccdot%20sin%28t%29)
Simplify the denominator on the LHS (Left Hand Side)
We get:
![cos(t) \cdot sin(t) = cos(t) \cdot sin(t)](https://tex.z-dn.net/?f=cos%28t%29%20%5Ccdot%20sin%28t%29%20%3D%20cos%28t%29%20%5Ccdot%20sin%28t%29)
LHS = RHS
Therefore, identity is verified.
Answer: Undefined
Step-by-step explanation:
4/0 is undefined. This is because any number divided by zero is undifined.
Answer:
where are the triangles????
A) <span>5x^2-13x-6
1. First, you must find the roots of the quadratic equation, by applying the quadratic formula, which is:
x=-b</span>√(b²-4ac)/2a
<span>
2. The roots are:
x1=3
x2=-2/5
3. Then, you have:
5(x-3)(x+2/5)
4. When you simplify, you obtain:
(x-3)(5x+2)
B) </span>4x^4-28x^3+48x^2<span>
1. First, you must factor the common term, which is 4x</span>^2. Then:
<span>
4x</span>^2(x^2-7x+12)
<span>
2. Now, you must apply the quadratic formula to obtain the roots of the quadratic equation: </span>x^2-7x+12. Then, you have:
x1=4
x2=3
3. Finally, you obtain:
4x^2(x-4)(x-3)
Answer:
r*6 + b*2
(a brainliest would be appreciated)