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Goshia [24]
3 years ago
11

Suppose that X is the number of hours that a computer is used in a computer lab on campus. The table below is the probability di

stribution for X. What is the expected value of X, that is, what is the mean its distribution?X 0 1 2 3 4Probability 0.2 0.2 0.4 0.15 0.05A. 0.8 B. 1.0 C. 1.65 D. 2
Mathematics
1 answer:
irina [24]3 years ago
3 0

Answer:

Option C: E(X) = 1.65

Step-by-step explanation:

Expected value of X, E(X) = ∑XP(X)

∑ = Summation

X = number of hours

P(X) = probability of a certain number of hours

E(X) = (0*P(X=0)) + (1*P(X=1)) + (2*P(X=2)) + (3*P(X=3)) + (4*P(X=4))

E(X) = (0*0.2) + (1*0.2) + (2*0.4) + (3*0.15) + (4*0.05)

E(X) = 0 + 0.2 + 0.8 + 0.45 + 0.20 = 1.65

E(X) = 1.65 - Option C

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EXPLANATION

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We complete the square to obtain,


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{x}^{2}  - 8x+  {y}^{2}  - 6y  =  - 24
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Answer:

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