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Goshia [24]
3 years ago
11

Suppose that X is the number of hours that a computer is used in a computer lab on campus. The table below is the probability di

stribution for X. What is the expected value of X, that is, what is the mean its distribution?X 0 1 2 3 4Probability 0.2 0.2 0.4 0.15 0.05A. 0.8 B. 1.0 C. 1.65 D. 2
Mathematics
1 answer:
irina [24]3 years ago
3 0

Answer:

Option C: E(X) = 1.65

Step-by-step explanation:

Expected value of X, E(X) = ∑XP(X)

∑ = Summation

X = number of hours

P(X) = probability of a certain number of hours

E(X) = (0*P(X=0)) + (1*P(X=1)) + (2*P(X=2)) + (3*P(X=3)) + (4*P(X=4))

E(X) = (0*0.2) + (1*0.2) + (2*0.4) + (3*0.15) + (4*0.05)

E(X) = 0 + 0.2 + 0.8 + 0.45 + 0.20 = 1.65

E(X) = 1.65 - Option C

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Brielle and Joshua are running a half marathon race, which is
Salsk061 [2.6K]

Answer and Explanation:

Brielle will run the marathon faster.

Work:

Brielle: 13.1/1.25=10.48*10=104.8 minutes

Joshua: 13.1/1.5=8.73...*18=157.2 minutes

Brielle finished in 104.8 minutes.

Joshua finished in 157.2 minutes.

Brielle finished the half marathon race by 52.5 minutes faster than Joshua.

Hope this helps!!! PLZ MARK BRAINLIEST!!!

7 0
3 years ago
What is the slope of a line perpendicular to AB if A (-2,-1) and B (0,4)
Nata [24]

Answer:

hgrtghjthweg

Step-by-step explanation:

7 0
3 years ago
A simple random sample of size nequals40 is drawn from a population. The sample mean is found to be 103.9​, and the sample stand
yan [13]

Answer:

There is enough evidence to support the claim that the population mean is greater than 100

Step-by-step explanation:

<u>Step 1</u>: We state the hypothesis and identify the claim

H_0:\mu=100 and H_1:\mu \:>\:100 (claim)

<u>Step 2</u>: Calculate the test value.

t=\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }

\implies t=\frac{103.9-100}{\frac{21.9}{\sqrt{40} } }=1.1263

<u>Step 3</u>: Find the P-value. The p-value obtained from a calculator is using d.f=39 and test-value 1.126 is 0.134

<u>Step 4</u>: We fail to reject the null hypothesis since P-value  is greater that the alpha level. (0.134>0.05).

<u>Step 5</u>: There is enough evidence to support the claim that the population mean is greater than 100.

<u>Alternatively</u>: We could also calculate the critical value to obtain +1.685 for \alpha=0.05 and d.f=39 and compare to the test-value:

The critical value (1.685>1.126) falls in the non-rejection region. See attachment.

NB: The t- distribution must be used because the population standard deviation is not known.

5 0
3 years ago
A clerk at Agency Y has determined that at speeds of 25 pages per minute it is typical for 3 out of every 100 pages she photocop
nalin [4]

Answer:

180 pages

Step-by-step explanation:

Since her photocopy session is 25 pages per minute, the total number of pages photocopied in 4 hour session can be calculated as;

number of pages = time × speed

                                 = (4 × 60) × 25

                                 = 240 ×25

                                 = 6000 pages

Thus, number of pages photocopied in 4 hours is 6000.

For every 100 pages, 3 would contain some type of printing error. The number of pages she expect with printing error during 4 hour session can be determined as;

           = \frac{6000}{100} × 3

           = 60 × 3

           = 180 pages

The expected number of pages with printing error during 4 hour photocopying session is 180 pages.

3 0
3 years ago
"write an expression that evaluates to true if the value of the integer variable x is divisible (with no remainder) by the integ
AysviL [449]

Solution:

As we have to write an expression , which evaluates to true if the value of the integer variable x is divisible (with no remainder) by the integer variable y, y≠0.

so, when x is divided by y we should get remainder as 0.

Using Euclid division lemma

x= y* q + m, i.e when an integer x is divided by y gives quotient q and remainder m.

Here , m=0

So, x = q * y

So, the expression which describes the above relationship is ,

\frac{x}{y}=q, where q is Quotient.


8 0
3 years ago
Read 2 more answers
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