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vlabodo [156]
3 years ago
8

Given that a=4 and b=5. evaluate : a²+3b​

Mathematics
2 answers:
Alenkinab [10]3 years ago
8 0

Answer:

31 is the correct answer

Step-by-step explanation:

Hope this helps! have a nice day! Please consider making me Brainliest!

andreev551 [17]3 years ago
3 0

Answer:

31

Step-by-step explanation:

4 squared is 16, and 5 times 3 is fifteen if you add them you get 31

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Draw a diagram that shows 1/5 times 30 equals 6
MrMuchimi

Total number = 30

1/5 of 30 = 1/5 x 30 = 6

The attached figures show the total number of filled circles in five lines. Each line have “6” filled circles.

So 5 lines having 6 filled circles = 5 x 6 = 30

<span>Every line represents “1/5” of total amount “30”. Which proved that 1/5 of 30 is equal to 6. </span>

3 0
3 years ago
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The sum of two numbers is 48 . The larger number is 12 more than the smaller number. What are the numbers?
SSSSS [86.1K]

Answer:

Smaller is 18 and larger be 30

Step-by-step explanation:

5 0
3 years ago
Is this graph a linear or no linear function?
olga2289 [7]

it is nonlinear function

5 0
3 years ago
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Please help me, its just question 11-14 !!
emmainna [20.7K]

Answer:

11- 64 degrees

12- 66 degrees

13- 89 degrees

14- 99 degrees

Step-by-step explanation:

11. 100 + 130 + 66 = 296

360 - 296 = <u>64</u>

12. 103 + 133 + 58 = 294

360 - 294 = <u>66</u>

13. 154 + 88 + 29 = 271

360 - 271 = <u>89</u>

14. 101 + 92 + 68 = 261

360 - 261 = <u>99</u>

hope this helps :)

4 0
3 years ago
If X²⁰¹³ + 1/X²⁰¹³ = 2, then find the value of X²⁰²² + 1/X²⁰²² = ?​
enyata [817]

Step-by-step explanation:

\bf➤ \underline{Given-} \\

\sf{x^{2013} + \frac{1}{x^{2013}} = 2}\\

\bf➤ \underline{To\: find-} \\

\sf {the\: value \: of \: x^{2022} + \frac{1}{x^{2022}}= ?}\\

\bf ➤\underline{Solution-} \\

<u>Let us assume that:</u>

\rm: \longmapsto u =  {x}^{2013}

<u>Therefore, the equation becomes:</u>

\rm: \longmapsto u +  \dfrac{1}{u}  = 2

\rm: \longmapsto \dfrac{  {u}^{2} + 1}{u}  = 2

\rm: \longmapsto{u}^{2} + 1 = 2u

\rm: \longmapsto{u}^{2} - 2u + 1 =0

\rm: \longmapsto  {(u - 1)}^{2} =0

\rm: \longmapsto u = 1

<u>Now substitute the value of u. We get:</u>

\rm: \longmapsto {x}^{2013}  = 1

\rm: \longmapsto x = 1

<u>Therefore:</u>

\rm: \longmapsto {x}^{2022}  +  \dfrac{1}{ {x}^{2022} }  = 1 + 1

\rm: \longmapsto {x}^{2022}  +  \dfrac{1}{ {x}^{2022} }  = 2

★ <u>Which is our required answer.</u>

\textsf{\large{\underline{More To Know}:}}

(a + b)² = a² + 2ab + b²

(a - b)² = a² - 2ab + b²

a² - b² = (a + b)(a - b)

(a + b)³ = a³ + 3ab(a + b) + b³

(a - b)³ = a³ - 3ab(a - b) - b³

a³ + b³ = (a + b)(a² - ab + b²)

a³ - b³ = (a - b)(a² + ab + b²)

(x + a)(x + b) = x² + (a + b)x + ab

(x + a)(x - b) = x² + (a - b)x - ab

(x - a)(x + b) = x² - (a - b)x - ab

(x - a)(x - b) = x² - (a + b)x + ab

6 0
3 years ago
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