Question

What is the simplified form of StartRoot 64 x Superscript 16 Baseline EndRoot?

Answer 1

Answer:

the correct answer on E2020 is 8r to the 4th power

Step-by-step explanation:

I just took the test and this was the correct answer for me.

Answer 2

Answer:

$8x^8$ (Please see my interpretation of the problem.)

The problem:

Simplify $\sqrt{64x^{16}}$ (Please tell me if I did or didn't interpret your problem correctly. Thank you!)

Step-by-step explanation:

$\sqrt{64x^{16}}$    (Given)

$\sqrt{64}\sqrt{x^{16}}$ (if u and v are positive then $\sqrt{uv}=\sqrt{u}\sqrt{v}$)

$8\sqrt[2]{x^{16}}$  ($\sqrt{ }=\sqrt[2]{}$)

$8x^{\frac{16}{2}}$  ($\sqrt[n]{x^m}=x^\frac{m}{n}$)

$8x^8$   (simplified/reduced the fractional-exponent)