Sixty percent of the students at a certain school wear neither a ring nor a necklace. Twenty percent wear a ring and 30 percent
wear a necklace. If one of the students is chosen randomly, what is the probability that this student is wearing (a) a ring or a necklace?
1 answer:
Answer:
0.4
Step-by-step explanation:
Given
60 % wear neither ring nor a necklace
20 % wear a ring
30 % wear necklace
This question can be Solved by using Venn diagram
If one person is choosen randomly among the given student the probability that this student is wearing a ring or necklace is
The sum of probabilty is equal to 1 because it completes the set
Therefore the required probabilty is 0.4
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Two options are given to Tina. We find how much she pays for each option, and the one in which she pays less offers the better value.
Tina sends 12 text messages each day in June
June has 30 days, so in June, Tina sent 12*30 = 360 text messages.
Package A:
First 100 messages cost 3p, the next 100 cost $2 and after that each costs $1.
She sends 360 messages, with:
The first 100 costing 3p.
The next 100 costing 2p.
The final 360 - 200 = 160 costing 1p.
She pays:
Package B:
2p for each message, 360 messages, so:
360*2p = 720p.
Which package is better?
Package A costs less, thus, it offers her the better value for money in 30 days.
Another example of a problem in which a person has to choose between two packages is given in brainly.com/question/10693932