Sixty percent of the students at a certain school wear neither a ring nor a necklace. Twenty percent wear a ring and 30 percent
wear a necklace. If one of the students is chosen randomly, what is the probability that this student is wearing (a) a ring or a necklace?
1 answer:
Answer:
0.4
Step-by-step explanation:
Given
60 % wear neither ring nor a necklace
20 % wear a ring
30 % wear necklace
This question can be Solved by using Venn diagram
If one person is choosen randomly among the given student the probability that this student is wearing a ring or necklace is


The sum of probabilty is equal to 1 because it completes the set
Therefore the required probabilty is 0.4
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Answer:The mean decreases by 18 and the median stays the same.
Step-by-step explanation:
Joan makes $275/week.
In addition to $275, she also makes 4 percent on sales over $1000.
So, 1250 - 1000 = 250.
Then 250(0.04) = 10.
Let t = amount of her paycheck for the week.
t = $275 + $10
t = $285
First isolate the power of 10 on the right side by dividing both sides by 5:

Now you're free to take the logarithm and simplify where you can:

Then solve for
:

B: 100,000 combinations because if you have 5 digits, your equation is 10^5 which equals 100,000,