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pychu [463]
3 years ago
9

Evaluate C= 2 A r, for r= 8.C=10,C = 16C= 28.7C= 16​

Mathematics
2 answers:
USPshnik [31]3 years ago
8 0

Answer: Second Option

C = 16\pi

Step-by-step explanation:

We are evaluating aarco lengths

The formula for the arc length is:

C = 2\pi r

We want to know what is the arc length for a radius of r = 8

Then we substitute r = 8 in the equation and solve

C = 2 \pi * 8

C = 16\pi

The correct answer is the second option

Anarel [89]3 years ago
3 0

Answer:

Correct choice is C=16 \pi.

Step-by-step explanation:

Given equation is C=2 \pi r.

Now we need to find the value of C using given equation C=2 \pi r and r=8.

To find that, we just need to plug r=8 into C=2 \pi r and simplify.

C=2 \pi r

C=2 \pi \times 8

C=16 \pi

Hence correct choice is C=16 \pi.

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Point E is the midpoint of AB and point F is the midpoint
GREYUIT [131]

The options are;

1) AB is bisected by CD

2) CD is bisected by AB

3) AE = 1/2 AB

4) EF = 1/2 ED

5) FD= EB

6) CE + EF = FD

Answer:

Options 1, 3 & 6 are correct

Step-by-step explanation:

We are told that Point E is the midpoint of AB. Thus, any line that passes through point E will bisect AB into two equal parts.

The only line passing through point E is line CD.

Thus, we can say that line AB is bisected by pine CD. - - - (1)

Also, since E is midpoint of Line AB, it means that;

AE = EB

Thus, AE = EB = ½AB - - - (2)

Also, we are told that F is the mid-point of CD.

Thus;

CF = FD

Point E lies between C and F.

Thus;

CE + EF = CF

Since CF =FD

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