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pychu [463]
3 years ago
9

Evaluate C= 2 A r, for r= 8.C=10,C = 16C= 28.7C= 16​

Mathematics
2 answers:
USPshnik [31]3 years ago
8 0

Answer: Second Option

C = 16\pi

Step-by-step explanation:

We are evaluating aarco lengths

The formula for the arc length is:

C = 2\pi r

We want to know what is the arc length for a radius of r = 8

Then we substitute r = 8 in the equation and solve

C = 2 \pi * 8

C = 16\pi

The correct answer is the second option

Anarel [89]3 years ago
3 0

Answer:

Correct choice is C=16 \pi.

Step-by-step explanation:

Given equation is C=2 \pi r.

Now we need to find the value of C using given equation C=2 \pi r and r=8.

To find that, we just need to plug r=8 into C=2 \pi r and simplify.

C=2 \pi r

C=2 \pi \times 8

C=16 \pi

Hence correct choice is C=16 \pi.

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Answer:

x = 9.25

Step-by-step explanation:

It is given that ABC is an isosceles triangle.

m∠A = 43° and m∠C = (6x+13)°

We need to find the value of x.

The sum of a triangle is equal to 180°.

∠A is the vertex angle. For a triangle sum of angle of triangle is equal to 180°

∠A+∠B +∠C=180

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6x+∠B = 124

∠B =124-6x

For an isosceles triangle,

∠B = ∠C

124-6x = (6x+13)

124-13 = 6x+6x

111 = 12x

x = 9.25

So, the value of x is 9.25.

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