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3 years ago

Jenna drove 35 miles in 30 minutes. At this rate, how many miles will she drive in 1 hour?

Mathematics

2 answers:

Llana [10]3 years ago

4 0

Answer:

70 miles

Step-by-step explanation:

30 minn+30 min=1 hour/60 min

30 min=35 miles

add the minutes together then add the miles together witch will give you

1 hour/60 min=70 miles

kykrilka [37]3 years ago

3 0

Answer:

70 miles

1 hour= 60 minutes

$60 \div 30 = 2$

Take 35 and multiply it by your first equations sum

$35 \times 2 =$

=70

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3 years ago

A major cab company in Chicago has computed its mean fare from O'Hare Airport to the Drake Hotel to be $28.75 , with a standard

bulgar [2K]

Answer:

Following are the solution to the given choices:

Step-by-step explanation:

Using chebyshev's theorem :

$\to P(|(x-\mu)|\leq k \sigma)\geq 1- \frac{1}{k^2}\\\\here \\ \to \mu=28.75\\\\ \to \sigma=4.44$

In point a)

$\to |(x-\mu)|= |20.17-28.75|=8.58 and \sigma=4.44 \\\\so, \\k= \frac{ |(x-\mu)| }{\sigma}$

$= \frac{8.58}{4.44} \\\\ =1.9 \\\\ =2$

$value= (1- \frac{1}{k^2}) \times 100 \% =75\%$

In point b)

$\to (1- \frac{1}{k^2}) \times 100 \% =84\% \\\\\to (1- \frac{1}{k^2})=0.84 \\\\\to \frac{1}{k^2} =0.16 \\\\\to \frac{1}{k}=0.4\\\\ \to k=2.5 \\\\\to |(x-\mu)| \leq k \sigma \\\\= |(x-\mu)|\leq 2.5 \times 4.44 \\\\ = |(x-\mu)|\leq 1.11 \\\\ = (28.75\pm 11.1) \\\\\to \text{fares lies between}(17.65,39.85)$