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3 years ago

A car breaks from a speed of 108km/h to 72km/h during a displacement of 100m, what is its aceleration ?

Mathematics

1 answer:

sergejj [24]3 years ago

4 0

First, note that 100 m = 0.100 km.

Recall that

v² - u² = 2 a ∆x

where u and v are initial and final velocities; a is acceleration; and ∆x is displacement. Solve for a :

(72 km/h)² - (108 km/h)² = 2 a (0.100 km)

a = ((72 km/h)² - (108 km/h)²) / (0.200 km)

a = -32,400 km/h²

If you want to convert this to m/s², we have

(-32,400 km/h²) = (-32,400 km/h²) (1000 m/km) (1/3600 h/s)²

(-32,400 km/h²) = -2.50 m/s²

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melamori03 [73]

$\bf \qquad \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\to &\$4432.37\\
P=\textit{original amount deposited}\to &\$3000\\
r=rate\to r\%\to \frac{r}{100}\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
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\end{array}\to &1\\
t=years\to &8
\end{cases}$

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\\\\\\
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\\\\\\
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3 years ago

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hodyreva [135]

Answer:

n = -6

x = -7

n = 27

Step-by-step explanation:

Question 1

-3n - n + 12 = 36

First we get all the variables to one side using subtraction property of equality.

-3n - n + 12 (-12) = 36 (-12)

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divide by the coefficient of n to isolate the variable

-4n/-4 = 24/-4

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3 years ago

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A car breaks from a speed of 108km/h to 72km/h during a displacement of 100m, what is its aceleration ?​

A car breaks from a speed of 108km/h to 72km/h during a displacement of 100m, what is its aceleration ?