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suter [353]
3 years ago
5

A car breaks from a speed of 108km/h to 72km/h during a displacement of 100m, what is its aceleration ?​

Mathematics
1 answer:
sergejj [24]3 years ago
4 0

First, note that 100 m = 0.100 km.

Recall that

<em>v</em>² - <em>u</em>² = 2 <em>a</em> ∆<em>x</em>

where <em>u</em> and <em>v</em> are initial and final velocities; <em>a</em> is acceleration; and ∆<em>x</em> is displacement. Solve for <em>a</em> :

(72 km/h)² - (108 km/h)² = 2 <em>a</em> (0.100 km)

<em>a</em> = ((72 km/h)² - (108 km/h)²) / (0.200 km)

<em>a</em> = -32,400 km/h²

If you want to convert this to m/s², we have

(-32,400 km/h²) = (-32,400 km/h²) (1000 m/km) (1/3600 h/s)²

(-32,400 km/h²) = -2.50 m/s²

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