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suter [353]
3 years ago
5

A car breaks from a speed of 108km/h to 72km/h during a displacement of 100m, what is its aceleration ?​

Mathematics
1 answer:
sergejj [24]3 years ago
4 0

First, note that 100 m = 0.100 km.

Recall that

<em>v</em>² - <em>u</em>² = 2 <em>a</em> ∆<em>x</em>

where <em>u</em> and <em>v</em> are initial and final velocities; <em>a</em> is acceleration; and ∆<em>x</em> is displacement. Solve for <em>a</em> :

(72 km/h)² - (108 km/h)² = 2 <em>a</em> (0.100 km)

<em>a</em> = ((72 km/h)² - (108 km/h)²) / (0.200 km)

<em>a</em> = -32,400 km/h²

If you want to convert this to m/s², we have

(-32,400 km/h²) = (-32,400 km/h²) (1000 m/km) (1/3600 h/s)²

(-32,400 km/h²) = -2.50 m/s²

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D: x < 20

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-4x + 16 > -64

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3 0
3 years ago
A nature center offers 2 guided walks. The morning walk is two-third mile. The evening walk is three-sixths mile. Which walk is
MArishka [77]

Answer:

Evening walk is shorter.  

Step-by-step explanation:

We have been given that a nature center offers 2 guided walks. The morning walk is two-third mile. The evening walk is three-sixths mile. We are asked to find the shorter walk.

Let us compare both fractions by making the same denominator.

\text{Two-thirds}=\frac{2}{3}

\text{Two-thirds}=\frac{2\times2}{3\times2}

\text{Two-thirds}=\frac{4}{6}

\text{Three-sixth}=\frac{3}{6}

Upon making common denominator, we can see that two-thirds are equal to four sixths.

Since three-sixths is less than four-sixths, therefore, evening walk is shorter.

We will draw two rectangles, one with 6 sub-parts and other with three sub-parts.

We will shade 2 parts out of 3 sub-parts to represent 2/3 and shade 3 parts out of 6 sub-parts to represent 3/6.

Then we will further divide three sub-parts into 6 sub-parts as shown in the diagram that will represent 4/6.

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