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Alenkinab [10]
4 years ago
11

Point A(-2, 3) lies on a line with a slope of two. Describe how to find two points on the line on either side of A

Mathematics
1 answer:
Alex Ar [27]4 years ago
5 0
Use point slope form or slope int to create an equation that meets the requirements
y - 3 = 2(x + 3)
point slope form
y = 2x + 9
slope int form


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1. An object is blasted upward at an initial velocity of 320 ft/s. The height, h(t), of the object is a function of time, t (in
Maksim231197 [3]

Answer:

20 seconds

Step-by-step explanation:

roots are (0,0) and (20,0) so 20-0 will provide the time from takeoff to landing

8 0
3 years ago
In the figure, O is the center, PT and PR are tangents, and
Deffense [45]

Answer:

  b. 30°

Step-by-step explanation:

In quadrilateral OTPR, angles O and P are supplementary.

  angle P = 180° -angle O = 180° -150°

  angle P = 30° . . . . matches choice B

7 0
4 years ago
What type of number is √5?
uysha [10]

Answer:2.23607

Step-by-step explanation:

\sqrt{5} (cos(0) + i × sin (0))

\sqrt{5} (cos(π) + i × sin (π))

3 0
2 years ago
Select all the expressions that are equivalent to -36x + 54y - 90.
adelina 88 [10]

Answer:

-18(2x-3y+5)

-2(18x-27y+45)

5 0
3 years ago
Using the law of cosines, a=2.2
Shkiper50 [21]
Answer: 81°


Explanation:


1) Law of cosines:


In a triangle with sides a, b, c whose opposite angles are, respectively, A, B and C, the law of cosines states:


b² = a² + c² - 2 (a)(c) cos (B)


2) In the triangle of the figure you have


b = 4.0
B = ?
a = 2.2
c = 3.7

⇒ (4.0)² = (2.2)² + (3.7)² - 2 (2.2) (3.7) cos(B)

⇒ 16 = 4.84 + 13.69 - 16.28cos(B)

⇒ 16.28 cos(B) = 4.84 + 13.69 - 16 = 2.53

⇒ cos(B) = 2.53 / 16.28

⇒ X = arccos(2.53 / 16.28 ) = 81.06° ≈ 81°


7 0
4 years ago
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