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3 years ago

Which statement best describes a dominant allele

Biology

2 answers:

sweet [91]3 years ago

5 0

Answer:

B The version of the trait that is expressed over other alleles for the same trait I believe

MaRussiya [10]3 years ago

5 0

The Answer Is B! Hope you got it right

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Pick out the characteristics that make the pulmonary alveoli a place for gaseous exchange

Vladimir79 [104]

Answer:

Moist walls - gases dissolve in the moisture helping them to pass across the gas exchange surface. Permeable walls - allow gases to pass through. Extensive blood supply - ensuring oxygen rich blood is taken away from the lungs and carbon dioxide rich blood is taken to the lungs.

7 0

2 years ago

which combination of alleles could be produced in a gamete of an individual that has the genotype AaBbcc? A) abc B) AB C) Aa D)

qwelly [4]

Answer:b. AB

Explanation:

5 0

3 years ago

Which of the following best explains what would happen to animal cells if plant cells did not perform photosynthesis?

ololo11 [35]

Answer:

D. Animal cells would not have the materials needed to produce energy in cellular respiration.

Explanation:

6 0

3 years ago

Read 2 more answers

List the 3 types of cell junctions and state which is the most and least permeable.

Zanzabum

1) occluding junctions
2) anchoring junctions
3) communicating junctions
Occluding junctions do not totally seal the space between cells and the resulting permeability varies greatly. I would say anchoring junctions are most likely with one of the other 2 junctions being least permeable.

4 0

3 years ago

Proteus vulgaris has a doubling time of roughly 28 minutes. If an initial population of 500 cells is allowed to grow for 6 hours

romanna [79]

<u>Answer:</u> The final population of Proteus vulgaris after 6 hours is $3.71\times 10^{6}cells$

<u>Explanation:</u>

We are given:

Proteus vulgaris divides and doubles every 28 minutes

Total time given = 6 hours = 360 min (Conversion factor: 1 hr = 60 min)

Number of times Proteus vulgaris doubles in 6 hours = $\frac{360min}{28min}=12.857times$

Calculating the number of bacteria after 6 hours under ideal conditions:

We are given:

Initial population = 500 cells

Number of times it doubles = 12.857 times

Final Proteus vulgaris population = $500\times 2^{12.857}=3709476.8=3.71\times 10^{6}cells$

Hence, the final population of Proteus vulgaris after 6 hours is $3.71\times 10^{6}cells$

8 0

3 years ago