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NeTakaya
3 years ago
8

Using the given equation find the missing coordinates of the points and then find the slope of the line for each equation

Mathematics
1 answer:
nekit [7.7K]3 years ago
3 0

Answer:

  A(2/9, 1/3)

  B(2/3, -1/3)

  slope = -1.5

Step-by-step explanation:

A graph can show the coordinates of interest: A(2/9, 1/3); B(2/3, -1/3).

Rearranging the equation to slope-intercept form, we have ...

  3y = -4.5x +2

  y = -1.5x +2/3

The slope is -1.5.

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Find to numbers, A & B,whose Products, A x B, is less than the sum, A + B. Can you find to positive numbers?
NeTakaya

Answer:

any number, n, multiplied by 1 is less than n + 1, so A = 1, B = any number

For example, 1 % 7. 1 * 7 = 7. 1 + 7 = 8

Also, having one of the variables be a decimal can make the numbers smaller.

For example, 28 * 0.5 = 14. 28 + 0.5 = 28.5

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3 years ago
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CaHeK987 [17]

Answer:

58

Step-by-step explanation:

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A stem-and-leaf plot is made using the following values. Which does NOT correctly represent a line of stem and leaves from the p
melomori [17]

Answer:

7

Step-by-step explanation:

70, 72, 72, 72, 74, 76

There are 6 numbers that have 7 as a 10. There are only 5 ones on the leaf of the stem 7. The 6 is missing.

5 0
3 years ago
The product of 5 and a number x is 1414 .
Julli [10]
5x = 1414
x = 1414 / 5
x = 282.80
4 0
3 years ago
The volume (in cubic inches) of a shipping box is modeled by V =2x³ -19x² +39x, where x is the length (in inches). Determine the
yawa3891 [41]

Answer:

The values of x for which the model is 0 ≤ x ≤ 3

Step-by-step explanation:

The given function for the volume of the shipping box is given as follows;

V = 2·x³ - 19·x² + 39·x

The function will make sense when V ≥ 0, which is given as follows

When V = 0, x = 0

Which gives;

0 = 2·x³ - 19·x² + 39·x

0 = 2·x² - 19·x + 39

0 = x² - 9.5·x + 19.5

From an hint obtained by plotting the function, we have;

0 = (x - 3)·(x - 6.5)

We check for the local maximum as follows;

dV/dx = d(2·x³ - 19·x² + 39·x)/dx = 0

6·x² - 38·x + 39 = 0

x² - 19/3·x + 6.5 = 0

x = (19/3 ±√((19/3)² - 4 × 1 × 6.5))/2

∴ x = 1.288, or 5.045

At x = 1.288, we have;

V = 2·1.288³ - 19·1.288² + 39·1.288 ≈ 22.99

V ≈ 22.99 in.³

When x = 5.045, we have;

V = 2·5.045³ - 19·5.045² + 39·5.045≈ -30.023

Therefore;

V > 0 for 0 < x < 3 and V < 0 for 3 < x < 6.5

The values of x for which the model makes sense and V ≥ 0 is 0 ≤ x ≤ 3.

8 0
3 years ago
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