I'm going with
<span>The things that you post online become public information.
and
</span><span>Employers screen job candidates based on social medias.
Because when you post online, you can very easily make your account private, or only share the post to a specified group of people.
Employers also screen job candidates based on their backround, personality, etc.</span>
Answer:
To find the text file, use a full path name when entering the file name, such as
C:\textfiles\StateCapitals.txt
You can save typing in the full path name by putting the file in the project directory, such as in
C:\Users\me\Documents\NetBeansProjects\Project4
Answer:
See explaination
Explanation:
Looking at telecommunications network, a link is a communication channel that connects two or more devices for the purpose of data transmission. The link is likely to be a dedicated physical link or a virtual circuit that uses one or more physical links or shares a physical link with other telecommunications links.
Please check attachment for further solution.
Answer:
hope this helps. I am also a learner like you. Please cross check my explanation.
Explanation:
#include
#include
using namespace std;
int main()
{
int a[ ] = {0, 0, 0}; //array declared initializing a0=0, a1=0, a3=0
int* p = &a[1]; //pointer p is initialized it will be holding the address of a1 which means when p will be called it will point to whatever is present at the address a1, right now it hold 0.
int* q = &a[0]; //pointer q is initialized it will be holding the address of a0 which means when q will be called it will point to whatever is present at the address a0, right now it hold 0.
q=p; // now q is also pointing towards what p is pointing both holds the same address that is &a[1]
*q=1
; //&a[0] gets overwritten and now pointer q has integer 1......i am not sure abut this one
p = a; //p is now holding address of complete array a
*p=1; // a gets overwritten and now pointer q has integer 1......i am not sure abut this one
int*& r = p; //not sure
int** s = &q; s is a double pointer means it has more capacity of storage than single pointer and is now holding address of q
r = *s + 1; //not sure
s= &r; //explained above
**s = 1; //explained above
return 0;
}
