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4 years ago

Helppppp pleaseeee !

Mathematics

2 answers:

igomit [66]4 years ago

6 0

The answer is B.) x2-14x+2y

pantera1 [17]4 years ago

5 0

B is the answer to your question.

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The perimeter of a square with side length s

lubasha [3.4K]

Answer:

Step-by-step explanation:

The perimeter of a square is 4 times it's side length.

Formula for a perimeter of a square: $4s$

s - side length

Hope this helps.

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3 years ago

Name the transformation in the picture 1

boyakko [2]

Answer:

DIALATION- REDUCTION

Step-by-step explanation:

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3 years ago

Read 2 more answers

What is the factor of 12

balu736 [363]

The factor of 12 is 1, 2 , 3 , 4 , 6 , 12

Hope it helps.

7 0

3 years ago

What ratio in simplest form. 36:12

Sergeeva-Olga [200]

Uh uh uh uh uh 3:1??

4 0

3 years ago

Number two please <br> ASAP

miv72 [106K]

The solutions for $-5 +2x^{2} = -6x$ is option 3. $x= \frac{-6 \pm \sqrt{36-4 (2)(-5)}}{4} .$

Step-by-step explanation:

Step 1:

First, we must bring the equation to the form of $ax^{2} +bx +c =0.$

So $-5 +2x^{2} = -6x$ becomes $2x^{2} +6x-5=0.$

The value of a is the coefficient of the $x^{2}$ term, the value of b is the coefficient of x term and c is the coefficient of the constant term.

Comparing the above equation to $ax^{2} +bx +c =0,$ we get $a = 2, b = 6,$ and $c=-5.$

We have the formula $x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}.$

Step 2:

By substituting the known values, we get

$x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a} =\frac{-6 \pm \sqrt{6^{2}-4 (2)(-5)}}{2 (2)}.$

$\frac{-6 \pm \sqrt{6^{2}-4 (2)(-5)}}{2 (2)} = \frac{-6 \pm \sqrt{36-4 (2)(-5)}}{4} .$

This is the third option.

8 0

4 years ago